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3 years ago

A balloon has a volume of 2.00 liters at STP. What will happen to the balloon's

Chemistry

1 answer:

Charra [1.4K]3 years ago

3 0

Answer:

The volume of the ballon decreases as much as the temperature is much cooler.

Explanation:

In the problem, the pressure remains constant whereas the temperature decreases. Charles's law states that the temperature is directly proportional to the volume under constant volume.

As in the problem the pressure remains constant but the temperature decreases:

The volume of the ballon decreases as much as the temperature is much cooler.

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An unknown substance turns blue litmus paper to red. Which additional test could be used to confirm the substance’s identity? It

Vedmedyk [2.9K]

Blue litmus paper turning red means that the solution where the litmus paper was submerged is an acidic solution with a pH of less than 7. Another verification of the nature of the solution is the turning to red of methyl orange in acidic solutions. The answer then is D.

5 0

3 years ago

Read 2 more answers

Consider the reaction pathway graph below.

san4es73 [151]

Hello!

If the reaction could be made to go faster B. The hill would be shorter.

The "hill" is called Activation Energy. It is the energy of the activated intermediate compound needed to complete the reaction. Catalysts are substances that don't intervene in the reaction which speed up the rate of a given reaction by lowering the Activation Energy giving alternate reaction pathways with lower-energy intermediates. If the reaction could be made to go faster with the use of a catalyst, then the Activation Energy would be lower and the "hill" would be shorter.

Have a nice day!

6 0

2 years ago

What kind of molecule is depicted here?

mina [271]

Explanation:

Methane molecule is depicted here

3 0

2 years ago

Read 2 more answers

Predict the direction in which the equilibrium will lie for the reactionC6H5COO- + HF C6H5COOH + F-.Ka(C6H5COOH) = 6.5 x 10-5; K

Llana [10]

Answer:

Equilibrium will lie to the right.

Explanation:

$K_{a}(HF)> K_{a}(C_{6}H_{5}COOH)$

That means HF is stronger acid than $C_{6}H_{5}COOH$ .

Alternatively, it can be said that $C_{6}H_{5}COO^{-}$ is a stronger base than $F^{-}$ .

Therefore HF readily gives proton to $C_{6}H_{5}COO^{-}$ to form $C_{6}H_{5}COOH$ and $F^{-}$ than the reverse reaction.

So, the equilibrium will lie more towards the right i.e. towards formation of $C_{6}H_{5}COOH$ and $F^{-}$ .

7 0

2 years ago

You measure 2.34 g of K2Cr2O7 into a volumetric flask. You dilute the K2Cr2O7 with water to a volume of 250 mL. It takes 35.7 mL

natta225 [31]

Answer:

0.191M of Na₂C₂O₄ is the concentration of the original Na₂C₂O₄ solution

Explanation:

The reaction of potassium dichromate, K₂Cr₂O₇ with sodium oxalate, Na₂C₂O₄ in the presence of acid H⁺ is:

K₂Cr₂O₇ + 3Na₂C₂O₄ + 14H⁺ → 2Cr³⁺ + 6CO₂ + 7H₂O + 6Na⁺ + 2K⁺

<em>Thus, 1 mole of K₂Cr₂O₇ reacts with 3 moles of Na₂C₂O₄</em>

Moles of 2.34g of K₂Cr₂O₇ (Molar mass: 294.185g/mol):

2.34g K₂Cr₂O₇ ₓ (1mol / 294.185g) = 7.954x10⁻³ moles K₂Cr₂O₇

In 250mL = 0.250L:

7.954x10⁻³ moles K₂Cr₂O₇ / 0.250L = 0.0318M K₂Cr₂O₇

Moles in 35.7mL = 0.0357L of this solution are:

0.0357L ₓ (0.0318mol / L) = <em>1.136x10⁻³ moles K₂Cr₂O</em>₇ in solution. As 1 mole of K₂Cr₂O₇ reacts with 3 moles of Na₂C₂O₄, to titrate the moles of K₂Cr₂O₇ in solution you need:

1.136x10⁻³ moles K₂Cr₂O₇ × (3 moles Na₂C₂O₄ / 1 mole K₂Cr₂O₇) =

<em>3.408x10⁻³ moles of Na₂C₂O₄</em>

In 17.8mL = 0.0178L:

3.408x10⁻³ moles of Na₂C₂O₄ / 0.0178L =

<h3>0.191M of Na₂C₂O₄ is the concentration of the original Na₂C₂O₄ solution</h3>

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3 0

2 years ago