Answer:
a) ionic b) polar covalent c) nonpolar covalent
Explanation:
To determine if a bond is covalent or ionic without knowing the electronegativities is to see if it is a metal-nonmetal bond or a nonmetal-nonmetal bond. Metal-nonmetal bonds are ALWAYS ionic, and nonmetal-nonmetal bonds are ALWAYS covalent. A is the metal-nonmetal bond and thus ionic. B & C are both nonmetal-nonmetal bonds and thus covalent.
Polarity:
To determine if a covalent bond is polar or not, we need to see how far apart the elements are away from one another. The further away the elements are from one another the more polar the bond. Nonmetal elements bonded to themselves are ALWAYS nonpolar see compound C. For B, the elements are far apart and are still covalent, so these bonds are polar.
Answer:
The maximum amount of work that can be done by this system is -2.71 kJ/mol
Explanation:
Maximum amount of work denoted change in gibbs free energy 
during the reaction.
Equilibrium concentration of B = 0.357 M
So equilibrium concentration of A = (1-0.357) M = 0.643 M
So equilibrium constant at 253 K, ![K_{eq}= \frac{[B]}{[A]}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%20%5Cfrac%7B%5BB%5D%7D%7B%5BA%5D%7D)
[A] and [B] represent equilibrium concentrations
When concentration of A = 0.867 M then B = (1-0.867) M = 0.133 M
So reaction quotient at this situation, 
We know, 
where R is gas constant and T is temperature in kelvin
Here R is 8.314 J/(mol.K), T is 253 K, Q is 0.153 and 
is 0.555
So, 
= -2710 J/mol
= -2.71 kJ/mol
Since there are no given items, I will give a general answer. Energy....or the lack of it. Examples: Heat, electricity, force (when an item is moving and it impacts something, it heats up...friction is an example of this), etc
i can think of 3 subatomic particles found in a nucleus protons, neutrons, and electrons
Answer: 0.27L
Explanation:
Given that,
Original volume V1 = 400.0 mL
convert volume in milliliters to liters
(If 1000mL = 1L
400.0 mL = 400.0/1000 = 0.4 L)
Original temperature T1 = 22.0 °C
Convert temperature in Celsius to Kelvin
(22.0 °C + 273 = 295K)
Original pressure = 1000mmHg
Convert pressure of 1000mmHg to atm
(If 760mmHg = 1 atm
1000mmHg = 1000/760 = 1.316 atm)
New volume V2 = ?
New Temperature T2 = 30.0°C
(30.0°C + 273 = 303K)
New pressure P2 = 2 atm
Since pressure, volume and temperature are involved, apply the general gas equation
(P1V1)T1 = (P2V2)/T2
(1.316 atm x 0.4 L) /295K = (2 atm x V2) /303K
0.526 atmL / 295K = 2V2 / 303K
Cross multiply
0.526 atmL x 303K = 2V2 x 295K
159.47 = 590V2
Divide both sides by 590
159.47/590 = 590V2/590
0.27 L = V2
Thus, the final volume of the gas is 0.27L
