SOMEONE HELP ME ANSWER FOSSIL RECORD PLS I DONT KNOW THE ANSWER I NEED TO KNOW ASAP
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Here the base is a benzoate ion, which is a weak base and reacts with water.
The equation indicates that for every mole of OH- that is produced , there is one mole of C6H5COOH produced.
Therefore [OH-] = [C6H5COOH]
In the question value of PH is given and by using pH we can calculate pOH and then using pOH we can calculate [OH-]
pOH = 14 - pH
pH given = 9.04
pOH = 14-9.04 = 4.96
pOH = -log[OH-] or
The base dissociation equation kb =
H2O(l) is not included in the 'kb' equation because 'solid' and 'liquid' are taken as unity that is 1.
Value of Kb is given =
And value of [OH-] we have calculated as and value of C6H5COOH is equal to OH-
Now putting the values in the 'kb' equation we can find the concentration of C6H5COO-
or
So, Concentration of NaC6H5COO would also be 0.76 M and volume is given to us 0.50 L , now moles can we calculated as : Moles = M X L
Moles of NaC6H5COO would be =
Moles of NaC6H5COO (sodium benzoate) = 0.38 mol