<u>Answer:</u> The volume of hydrogen gas required for the given amount of ethylene gas is 113 L
<u>Explanation:</u>
At STP:
1 mole of a gas occupies 22.4 L of volume
We are given:
Volume of ethylene = 113 L
For the given chemical equation:
By Stoichiometry of the reaction:
of ethylene reacts with of hydrogen gas
So, 113 L of ethylene gas will react with = 
of hydrogen gas
Hence, the volume of hydrogen gas required for the given amount of ethylene gas is 113 L
You can demonstrate that a piece of chalk has mass by putting it on a pan scale. Pan scales determine mass in grams. Also if the mass feels like it has some weight to it (although not to be confused with weight, they are two different things!), it most likely has mass.
Hope this helps!!
Answer:
Li2SO4
Explanation:
Balance the reaction of Li3PO4 + MgSO4 = Li2SO4 + Mg3(PO4)2 using this chemical equation balancer!
