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RSB [31]
2 years ago
14

SOMEONE HELP ME ANSWER FOSSIL RECORD PLS I DONT KNOW THE ANSWER I NEED TO KNOW ASAP

Chemistry
1 answer:
Gekata [30.6K]2 years ago
4 0

Answer:

I don't know if this helps but here

What did whales look like million years ago?

It lived in or near estuaries about 50 to 48 million years ago. Like Pakicetus, it spent time both in and out of water, but its large feet looked more like flippers than its ancestor's longer legs. ... This five-metre-long animal had proper flippers and tiny hind legs.

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A gold-colored ring has a mass of 17.5 grams and a volume of 0.82 mL. What is the density of this ring?
max2010maxim [7]

Answer:

21 g/mL

Explanation:

To solve this problem, first look at the density equation, which is D=M/V, which D stands for density, M stands for mass, and V stands for volume. When you substitute in the variables, you get D=17.5/.82, which is equivalent to 21.34. However, since we need to pay attention to the sig fig rules for multiplying, we need to have the same amount of sig figs as the value with the least amount of sig figs, which is the number .82. .82 has two sig figs, so you round down. Your answer will be 21 g/mL.

4 0
3 years ago
What is the energy of a photon of green light with a frequency of 5.80 x 10^14/s
dedylja [7]
I'm not understanding that much. but if i'm right the answer is <span>3.84 x 10^-19 J</span>
8 0
3 years ago
Use the periodic table to determine the electron configuration for Ca and Pm in noble-gas notation Ca: [Ar]4s2 [Ar]4s1 [Ar]3s2 [
sveta [45]
Answer:

1) Ca: [Ar]4s²
2) Pm: [Xe]6s²4f⁵

Explanation:

1) Ca:

Its atomic number is 20. So it has 20 protons and 20 electrons.

Since it is in the row (period) 4 the noble gas before it is Ar, and the electron configuration is that of Argon whose atomic number is 18.

So, you have two more electrons (20 - 18 = 2) to distribute.

Those two electrons go the the orbital 4s.

Finally, the electron configuration is [Ar] 4s².

2) Pm

The atomic number of Pm is 61, so it has 61 protons and 61 electrons.

Pm is in the row (period) 6. So, the noble gas before Pm is Xe.

The atomic number of Xe is 54.

Therefore, you have to distribute 61 - 54 = 7 electrons on the orbitals 6s and 4f.

The resultant distribution for Pm is: [Xe]6s² 4f⁵.
5 0
3 years ago
Read 2 more answers
The sun's inner core is the hottest part of the sun<br><br> true or false
harkovskaia [24]
False heat rises upwards therefore the hottest part of the sun would be upwards
3 0
3 years ago
Read 2 more answers
Formation of water: 2H2 + 1 O2 --&gt; 2H2O
noname [10]

Answer:

2.2 moles H2O

Explanation:

35g O_2 \mbox{ \cdot }\frac{1mol}{32g/mol} \mbox{ \cdot }\frac{2mol H_2O}{1mol O_2}= 2.1875, which rounds to about 2.2

7 0
1 year ago
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