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lesya [120]
3 years ago
8

(GIVING BRAINLIEST!!!)

Mathematics
1 answer:
Blizzard [7]3 years ago
6 0

Answer:

B) \displaystyle \frac{1}{16}

Step-by-step explanation:

\displaystyle \frac{1}{16} = \frac{\frac{1}{8}}{2} \\ \\ OR \\ \\ \frac{1}{8} \div 2 = \frac{1}{8} \times \frac{1}{2} = \frac{1}{16}

I am joyous to assist you at any time.

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Does this equation represent a function?<br> Answer Yes
snow_lady [41]

Answer:

yes

Step-by-step explanation:

ur welcome

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7 0
3 years ago
Find the product of 7x and 13x^2-8
Firdavs [7]
7x (13x^2 - 8) = 91x^3 - 56x
3 0
3 years ago
Divide 64.5 by 0.015, leaving the answer in standard form
belka [17]

Answer:

4.3 *10^3

Step-by-step explanation:

5 0
3 years ago
In the diagram below , tan theta =square root 3. What is the value of m?
vova2212 [387]

Answer:

m=\frac{\sqrt{3}}{2}

Step-by-step explanation:

we know that

In the diagram

tan(\theta)=\frac{m}{1/2}=2m

tan(\theta)=\sqrt{3}

Equate

2m=\sqrt{3}

m=\frac{\sqrt{3}}{2}

7 0
4 years ago
Cynthia Besch wants to buy a rug for a room that is 1919 ft wide and 2727 ft long. She wants to leave a uniform strip of floor a
yulyashka [42]

Answer:

The dimension of the rug would be 17 ft × 9 ft.

Step-by-step explanation:

Given

length of the room = 27 ft.

width of the room = 19 ft.

suppose, she leaves a uniform strip of x ft. around the rug.

So,

The length of rug = (27-2x)ft.

Width of rug= (19-2x)ft.

∴ Area of the rug= length×width

                            =  (27-2x)(19-2x)

                            =  513-54x-38x+4x^2

                            =   513-92x+4x^2

According to the question,

513-92x+4x^2=153

513-92x+4x^2-153=0        ( subtract 153 both sides)

4x^2-92x+360=0

4(x^2-23x+90)=0

x^2-23x+90=0

x^2-(18+5)x+90=0            ( Middle term splitting)

x^2-18x-5x+90=0

x(x-18)-5(x-18)=0

(x-5)(x-18)=0

x-5=0 or x-18=0             ( zero product property)

x=5 or x=18

if x=18, dimension would be negative  ( Not possible)

Thus, x= 5

Hence,

length of rug= 27-10=17 ft.

width of rug= 19-10=9 ft.

8 0
4 years ago
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