Answer:
23.094 ft approximately
(If you want your answer in a different format, let me know please.)
Step-by-step explanation:
I would have solve this using tangent since the side opposite to x is asked for and the adjacent side to side is given as having a measurement of 40 ft.
But I think they want you to use the formula:
.

Input into calculator:
(approximation)
l represents the length of the roof.
So we have l=46.188 and b=40.
We must use the Pythagorean Theorem to find the height,h, for of the roof.
l is the hypotenuse.


Subtract 1600 on both sides:

Take square root of both sides:

The answer is 23.094 feet for the height that roof reaches on the building.
I want to show you another way:


Multiply both sides by 40:

Input into calculator:

I didn't do it this way because your problem suggested you use their formula to find the height.