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murzikaleks [220]
3 years ago
12

Next in sequence 9/16, -9/8, 9/4, -9/2, 9, ?

Mathematics
1 answer:
Fudgin [204]3 years ago
5 0

Answer:

-18

Step-by-step explanation:

*2, *(-2), *2, *(-2) ...

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Simplify.<br><br> 4 x (8 + 5) + 9 can someone help me out plz
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Step-by-step explanation:

4x(8+5)+9

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=52x+9

Description:

The first step is to simplify the equation provided. So in this case the equation is 4 x (8 + 5) + 9.  After that you will get your answer as =52x+9. So in this case 4 x (8 + 5) + 9 = =52x+9.

Answer: =61

Hope this helps.

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How to prove this???
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go to right side now

4( \cos^6 A - \sin^6 A)\\&#10;\Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A)

use x^3 - y^3 = (x-y)(x^2 + xy + y^2) and x^3 + y^3 = x^2 - xy + y^2

4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A) \\&#10;\Rightarrow  4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\&#10;~\quad  \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A)

so \sin^2 A + \cos^2 A = 1

4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\ ~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 + \cos A \sin A )(1- \cos A \sin A ) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \cos^2 A \sin^2 A )\\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \sin^2 A \cos^2 A ) \\&#10; \Rightarrow Left hand side
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