the question in English
Mateo will reproduce a photo measuring 5 cm per side on a scale of 3/4
How much will the square side of the copy measure?
Will the size of the copy be larger or smaller than the original?
we know that
the scale factor is equal to 
Let
x----------> the original length side
y--------> the copy length side
we have that
substitute the values
therefore
<u>the answer Part a) is </u>
the length side of the copy measure is 
Part b)
we know that
the size of the original photo is------> 
the size of the copy is------> 
so
therefore
<u>the answer part b) is</u>
The size of the copy be smaller than the original
Answer:
the area would be 36(pi) since you can't find out the exact value of pi (22/7) and where it would terminate so thats the most exact answer you can get. The circumference would be
Step-by-step explanation:
12/2 = 6
Area = (pi)radius^2
6^2 = 36
36(pi)
Circumference: (pi)d
12(pi)
For approximate area you multiply r^2 by 3.14
For approximate circumference you multiply diameter by 3.14
Rules of exponents and the distributive property apply.
(x+y)² = (x+y)·(x+y) . . . . . meaning of exponent of 2
= x·(x+y) +y·(x+y) . . . . . . . distributive property
= x·x +x·y +y·x +y·y . . . . . distributive property
= x² +x·y +x·y +y² . . . . . . meaning of exponent of 2, commutative property of multiplication
= x² +(1+1)·x·y +y² . . . . . . distributive property
= x²+2xy+y² . . . . . . . . . the desired form
Thus
(x+y)² = x²+2xy+y²
Since he sold it for $75 more,
% Mark Up = Mark Up/ Cost Price x 100%
% Mark Up = 75 / 125 x 100% = 0.6 x 100% = 60%
Percent Mark Up = 60%
Hope this helps :)
Given that percent of computer infected which is found by quality control inspector = 1.3%
Total number of computers = 1500
Now we have to find the number of Defective computer. To find that we will just need to find the product of given defective percent by the total number of computers.
Total number of defective computers = 1.3% of 1500
Total number of defective computers = 0.013* 1500
Total number of defective computers = 19.5
Hence final answer is approx 20 computers.
