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soldi70 [24.7K]
2 years ago
14

In ΔBCD, \overline{BD}

Mathematics
1 answer:
Alex787 [66]2 years ago
4 0

Answer:

30degrees

Step-by-step explanation:

Given

Exterior angle m<CDE = 7x - 19 degrees

interior angles are

m<BCD = 2x - 1

m<DBC = x+10

Since the sum of the interior angles is equal to the exterior, hence;

2x - 1 + x+10 = 7x - 19

3x + 9 = 7x - 19

3x - 7x = -19 - 9

-4x = -28

x = 28/4

x = 7

Get m<CDE

m<CDE = 7x - 19

m<CDE = 7(7) - 19

m<CDE = 49 - 19

m<CDE = 30degrees

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Please help me out with the odds on this one (IMPORTANT) *determine whether the given relation is a function*
Hitman42 [59]

Answer:

It's not a function.

Step-by-step explanation:

3 0
3 years ago
Find the mass of the lamina that occupies the region D = {(x, y) : 0 ≤ x ≤ 1, 0 ≤ y ≤ 1} with the density function ρ(x, y) = xye
Alona [7]

Answer:

The mass of the lamina is 1

Step-by-step explanation:

Let \rho(x,y) be a continuous density function of a lamina in the plane region D,then the mass of the lamina is given by:

m=\int\limits \int\limits_D \rho(x,y) \, dA.

From the question, the given density function is \rho (x,y)=xye^{x+y}.

Again, the lamina occupies a rectangular region: D={(x, y) : 0 ≤ x ≤ 1, 0 ≤ y ≤ 1}.

The mass of the lamina can be found by evaluating the double integral:

I=\int\limits^1_0\int\limits^1_0xye^{x+y}dydx.

Since D is a rectangular region, we can apply Fubini's Theorem to get:

I=\int\limits^1_0(\int\limits^1_0xye^{x+y}dy)dx.

Let the inner integral be: I_0=\int\limits^1_0xye^{x+y}dy, then

I=\int\limits^1_0(I_0)dx.

The inner integral is evaluated using integration by parts.

Let u=xy, the partial derivative of u wrt y is

\implies du=xdy

and

dv=\int\limits e^{x+y} dy, integrating wrt y, we obtain

v=\int\limits e^{x+y}

Recall the integration by parts formula:\int\limits udv=uv- \int\limits vdu

This implies that:

\int\limits xye^{x+y}dy=xye^{x+y}-\int\limits e^{x+y}\cdot xdy

\int\limits xye^{x+y}dy=xye^{x+y}-xe^{x+y}

I_0=\int\limits^1_0 xye^{x+y}dy

We substitute the limits of integration and evaluate to get:

I_0=xe^x

This implies that:

I=\int\limits^1_0(xe^x)dx.

Or

I=\int\limits^1_0xe^xdx.

We again apply integration by parts formula to get:

\int\limits xe^xdx=e^x(x-1).

I=\int\limits^1_0xe^xdx=e^1(1-1)-e^0(0-1).

I=\int\limits^1_0xe^xdx=0-1(0-1).

I=\int\limits^1_0xe^xdx=0-1(-1)=1.

No unit is given, therefore the mass of the lamina is 1.

3 0
3 years ago
Solve 3.4m = 204<br> The solution is m
Sophie [7]
60! 3.4(60)=204 so the answer is 60
8 0
3 years ago
How to evaluate the expression
jasenka [17]

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1

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Edit reason: typo

4 0
3 years ago
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Kipish [7]
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8 0
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