Question

F(x)=" class="latex-formula"> and g(x)=$x^{2}$

find f(g(-6)

Answer 1

Answer:

$f(g(-6))=2\sqrt{10}$

Step-by-step explanation:

first we need to find g(-6)

$g(x)= x^2\\\\g(-6)=(-6)^2\\\\g(-6)=36$

so g(-6)=36

so we need to find f(36)

$f(x)=\sqrt{x+4} \\\\f(36)=\sqrt{36+4} \\\\f(36)=\sqrt{40}\\\\f(36)=\sqrt{4}* \sqrt{10} \\\\f(36)=2\sqrt{10}$

so that's answer

$f(g(-6))=2\sqrt{10}$