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3 years ago

13

F(x)=

" class="latex-formula"> and g(x)= $x^{2}$

find f(g(-6)

1 answer:

prisoha [69]3 years ago

8 0

Answer:

$f(g(-6))=2\sqrt{10}$

Step-by-step explanation:

first we need to find g(-6)

$g(x)= x^2\\\\g(-6)=(-6)^2\\\\g(-6)=36$

so g(-6)=36

so we need to find f(36)

$f(x)=\sqrt{x+4} \\\\f(36)=\sqrt{36+4} \\\\f(36)=\sqrt{40}\\\\f(36)=\sqrt{4}* \sqrt{10} \\\\f(36)=2\sqrt{10}$

so that's answer

$f(g(-6))=2\sqrt{10}$

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Answer:

a) 80% probability that he wins at least one race.

b) 30% probability that he wins exactly one race.

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Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that he wins the first race.

B is the probability that he wins the second race.

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We have that:

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In which a is the probability that he wins the first race but not the second and $A \cap B$ is the probability that he wins both these races.

By the same logic, we have that:

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This means that $A \cap B = 0.5$

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This means that $B = 0.6$

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$0.7 = a + 0.5$

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B) he wins exactly one race.

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There is a 30% probability that he wins exactly one race.

C) he wins neither race

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From a), we have that there is an 80% probability that he wins at least one race.

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