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4 years ago

13

F(x)=

" class="latex-formula"> and g(x)= $x^{2}$

find f(g(-6)

1 answer:

prisoha [69]4 years ago

8 0

Answer:

$f(g(-6))=2\sqrt{10}$

Step-by-step explanation:

first we need to find g(-6)

$g(x)= x^2\\\\g(-6)=(-6)^2\\\\g(-6)=36$

so g(-6)=36

so we need to find f(36)

$f(x)=\sqrt{x+4} \\\\f(36)=\sqrt{36+4} \\\\f(36)=\sqrt{40}\\\\f(36)=\sqrt{4}* \sqrt{10} \\\\f(36)=2\sqrt{10}$

so that's answer

$f(g(-6))=2\sqrt{10}$

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