we know that a₁ = 1, and aₙ = aₙ₋₁ + 2, is another way of saying, we add 2 to get the next term, namely, 2 is the common difference.
![\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\[-0.5em] \hrulefill\\ a_1=1\\ d=2\\ n=7 \end{cases} \\\\\\ a_7=1+(7-1)2\implies a_7=1+12\implies a_7=13](https://tex.z-dn.net/?f=%5Cbf%20n%5E%7Bth%7D%5Ctextit%7B%20term%20of%20an%20arithmetic%20sequence%7D%0A%5C%5C%5C%5C%0Aa_n%3Da_1%2B%28n-1%29d%5Cqquad%0A%5Cbegin%7Bcases%7D%0An%3Dn%5E%7Bth%7D%5C%20term%5C%5C%0Aa_1%3D%5Ctextit%7Bfirst%20term%27s%20value%7D%5C%5C%0Ad%3D%5Ctextit%7Bcommon%20difference%7D%5C%5C%5B-0.5em%5D%0A%5Chrulefill%5C%5C%0Aa_1%3D1%5C%5C%0Ad%3D2%5C%5C%0An%3D7%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0Aa_7%3D1%2B%287-1%292%5Cimplies%20a_7%3D1%2B12%5Cimplies%20a_7%3D13)
25 - 6r = 25
-6r = 25-25
-6r = 0
r = 0/-6
r = 0
The product must be greater than 6,
because. 1-3/4 is greater than ' 1 '.
The product is "take 6 more than 1 time".
Step-by-step explanation:
the mean value is the sum of all values divided by how many values there are.
so,
(3 + -5 + 70 + -90 + -13) / 5 = -35/5 = -7
-7° F is the mean temperature of the 5 cities.
Chance to draw 7: 4 out of 52
chance to draw 1st queen: 4 out of 51
chance to draw 2nd queen: 3 out of 50
total chance = multiplication of

times

times


pretty miserable change... apox 1 out of 2762, but still much better than any lottery ticket