im doing this problem right now---
ok so a1=256 a2=64 a3=15 a4=4... find a9
the sequence divides by 1/4 every term
an=a1*r^n-1
an=(256)*(1/4)^n-1
replace n with 9
A9=(256)*(1/4)^9-1
A9=(256)*(1/4)^8
=(256)*(1/4)
A9=64^8
1/256 or a9= 0.00390625
Answer:
70
Step-by-step explanation:
1. A
2. C
3. C
4. A
I’m not so sure about number 4 tho!!
If x=4, rewrite the equation which would be 5(4)+6
First you multiply 4 by 5 which would give you 20
Now put in the 6 in the equation
20+6
20+6=26
Therefore for the expression given the value of x would make your answer be 26
The intersection of the two sets is the list of members that appear in both sets. That is {3}.
Your statement is FALSE.
