What mass of calcium chloride will be produced from 3.750 moles of hcl reacting with ca(oh)2
1 answer:
Answer:
208.125g
Explanation:
Given parameters:
Number of moles of HCl = 3.75moles
Unknown:
Mass of CaCl₂ that will be produced = ?
Solution:
The reaction equation is given as:
2HCl + Ca(OH)₂ → CaCl₂ + 2H₂O
Now, to find the mass of CaCl₂, we have to work from the known to the unknown.
The known specie here is the number of moles of HCl;
2 mole of HCl will produce 1 mole of CaCl₂
3.75moles of HCl will produce = 1.875moles
The mass of CaCl₂;
Mass of CaCl₂ = number of moles of CaCl₂ x molar mass
Molar mass of CaCl₂ = 40 + 2(35.5) = 111g/mol
Mass of CaCl₂ = 1.875 x 111 = 208.125g
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Answer:
i. Molar mass of glucose = 180 g/mol
ii. Amount of glucose = 0.5 mole
Explanation:
<em>The volume of the glucose solution to be prepared</em> = 500
<em>Molarity of the glucose solution to be prepared</em> = 1 M
i. Molar mass of glucose () = (6 × 12) + (12 × 1) + (6 × 16) = 180 g/mol
ii.<em> mole = molarity x volume</em>. Hence;
amount (in moles) of the glucose solution to be prepared
= 1 x 500/1000 = 0.5 mole