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3 years ago

Lily has 4 parakeets. if lily keeps 4 parakeets in each cage, how many cages does she need

Mathematics

2 answers:

zimovet [89]3 years ago

8 0

Lily would need 4 cages

Colt1911 [192]3 years ago

7 0

If u mean 1 parakeet in each cage then she would need 4 cages my friend

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. Ana tiene el triple de edad que su hijo Jaime. Dentro de 15 años, la edad de Ana será el doble que la de su hijo. ¿Cuántos año

poizon [28]

Answer:

La madre de Jaime tiene 30 años más que él.

Step-by-step explanation:

Llamemos x a la edad actual de Jaime, si la edad actual de Ana es el triple que la de Jaime, entonces la edad actual de Ana es 3x.

Dentro de 15 años, la edad de Jaime será x+15 (edad actual más 15 años) y usando el mismo razonamiento, la edad de Ana será 3x + 15.

Por otro lado el problema nos dice que dentro de 15 años, la edad de Ana (que ya sabemos que será 3x + 15) será igual al doble de la que tendrá su hijo en 15 años. Esto en forma de ecuación se representa:

$3x+15=2(x+15)$ (la edad de Ana será igual que el doble de la de su hijo)

Resolviendo la ecuación:

$3x+15= 2(x+15)\\3x+15=2x+30\\3x-2x=30-15\\x=15$

Por lo tanto, Jaime tiene 15 años y su madre tiene $3x=3(15)=45$ años. Por lo tanto la diferencia de edad es de 30 años y Ana tiene 30 años más que su Jaime.

3 0

2 years ago

The region bounded by y=x^2+1, y=x, x=-1, x=2 with square cross sections perpendicular to the x-axis.

VLD [36.1K]

Answer:

The bounded area is 5 + 5/6 square units. (or 35/6 square units)

Step-by-step explanation:

Suppose we want to find the area bounded by two functions f(x) and g(x) in a given interval (x1, x2)

Such that f(x) > g(x) in the given interval.

This area then can be calculated as the integral between x1 and x2 for f(x) - g(x).

We want to find the area bounded by:

f(x) = y = x^2 + 1

g(x) = y = x

x = -1

x = 2

To find this area, we need to f(x) - g(x) between x = -1 and x = 2

This is:

$\int\limits^2_{-1} {(f(x) - g(x))} \, dx$

$\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx$

We know that:

$\int\limits^{}_{} {x} \, dx = \frac{x^2}{2}$

$\int\limits^{}_{} {1} \, dx = x$

$\int\limits^{}_{} {x^2} \, dx = \frac{x^3}{3}$

Then our integral is:

$\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx = (\frac{2^3}{2} + 2 - \frac{2^2}{2}) - (\frac{(-1)^3}{3} + (-1) - \frac{(-1)^2}{2} )$

The right side is equal to:

$(4 + 2 - 2) - ( -1/3 - 1 - 1/2) = 4 + 1/3 + 1 + 1/2 = 5 + 2/6 + 3/6 = 5 + 5/6$

The bounded area is 5 + 5/6 square units.

3 0

2 years ago

Roger and Rita each drive at a constant speed between Phoenix and San Diego. Each driver’s distance for the same section of the

motikmotik

Answer:

The one you chose in the image is correct (A)

7 0

2 years ago

Read 2 more answers

A bank loaned out $28,500, part of it at the rate of 14% annual interest, and the rest at 4% annual

Flauer [41]

Answer:

$15,000 was invested at 14% per year, and $13,500 was invested at 4% per year.

Step-by-step explanation:

Given that a bank loaned out $ 28,500, part of it at the rate of 14% annual interest, and the rest at 4% annual interest, and the total interest earned for both loans was $ 2,640.00, to determine how much was loaned at each rate you must perform the following calculations:

28,500 x 0.14 + 0 x 0.04 = 3,990

20,000 x 0.14 + 8,500 x 0.04 = 3,140

15,000 x 0.14 + 13,500 x 0.04 = 2,640

Therefore, $ 15,000 was invested at 14% per year, and $ 13,500 was invested at 4% per year.

5 0

2 years ago

Find the sum of the arithmetic series in which a1 = –68, d = –3, and n = 20.

harkovskaia [24]

Step-by-step explanation:

Sum of 20 terms in thr arithmetic sequence adds up to -1930

6 0

2 years ago