If’s chemistry it would be like this- Xe=1 and F=2/Xe=1 and F=6 so, to balance Xe=1 and F=[3x2]/Xe=1 and F=6.
Answer:
Explanation:
Given data:
Number of frame is 12+ 8 = 20
Total filtrate is 360 lb
we know
For 1 plate area 
Then for 20 are PLATE 
filtrate equation is given as
In the above equation only t and A is variable , all other terms are constant
Therefore we have
![\frac{t_2}{t_1}= \frac{A_1}{A_2} = [\frac{65}{105.33}]^2 = 0.36](https://tex.z-dn.net/?f=%5Cfrac%7Bt_2%7D%7Bt_1%7D%3D%20%5Cfrac%7BA_1%7D%7BA_2%7D%20%3D%20%5B%5Cfrac%7B65%7D%7B105.33%7D%5D%5E2%20%3D%200.36)
The formula of the molarity, M is: M = number of moles of solute / Volume of solution in liters.
Here number of moles of solute is 7.0 and volume of solution in liters = 569 mL / 1000 mL/L = 0.569 L
M = 7.0 moles / 0.569 liters = 12.3 M
Answer: 12.3 M
Answer:
Molecular formula: C₂H₄O₂
Empirical formula: CH₂O
Explanation:
40 % C, 6.72 % H and 53.29 % O states the centesimal composition of the compound. These data means that in 100 g of compound we have x grams of a determined element.
We divide the mass by the molar mass of each:
40 g / 12 g/mol = 3.33 moles of C
6.72 g / 1 g/mol = 6.72 moles of H
53.29 g / 16 g/mol = 3.33 moles of O
We can determine rules of three to get, the molecular formula.
In 100 g of compound we have 3.33 moles of C, 6.72 moles of H and 3.33 moles of O; therefore in 60 g (1 mol) we must have
- (60 . 3.33) / 100 = 2 moles of C
- (60 . 6.72) / 100 = 4 moles of H
- (60 . 3.33) / 100 = 2 moles of O
Molecular formula is C₂H₄O₂
Empirical formula has the lowest suscripts; we divide by two, so the empirical formula is CH₂O
Answer:
Dissolved minerals in the ground water precipitate (crystallize) from water in the pore spaces forming mineral crusts on the sedimentary grains, gradually cementing the sediments, thus forming a rock
Explanation:
