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mylen [45]
3 years ago
9

What molecules can be broken down to one Another ?

Chemistry
1 answer:
hjlf3 years ago
4 0

Answer:

compounds can be broken down to one another

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400 ms^2/0.080 s <br><br> solve
Nana76 [90]

Answer: 5000ms^2 s

Explanation:

5 0
3 years ago
An object with a mass of 10.0 kg is moving at a speed of 5.00m/s. The kinetic energy of the mass is
NemiM [27]
KE = (1/2)mv^2
m = 10.0 kg
v = 5.00 m/a

KE = (1/2)(10.0)(5.00)^2 = (1/2)(10.0)(25.0) = 125 J

C. 125 J
7 0
3 years ago
(a) show that the pressure exerted by a fluid P (in pascals) is given by P= hdg, where h is the column of the fluid in metres, d
Murrr4er [49]

Answer:

<em>56.4 m</em>

<em></em>

Explanation:

volume increases by factor of 6, i.e \frac{V2}{V1} = 6

Initial temperature T1 at bottom of lake =  5.24°C = 278.24 K

Final temperature T2 at top of lake = 18.73°C = 291.73 K

NB to change temperature from °C to K we add 273

Final pressure P2 at the top of the lake = 0.973 atm

Initial pressure P1 at bottom of lake = ?

Using the equation of an ideal gas

\frac{P1V1}{T1} = \frac{P2V2}{T2}

P1 = \frac{P2V2T1}{V1T2} = \frac{0.973*6*278.24}{291.73}

P1 = 5.57 atm

5.57 atm = 5.57 x 101325 = 564380.25 Pa

Density Ρ of lake = 1.02 g/cm^{3} = 1020 kg/m^{3}

acceleration due to gravity g = 9.81 m/s^{2}

Pressure at lake bottom = pgd

where d is the depth of the lake

564380.25 = 1020 x 9.81 x  d

d = \frac{564380.25}{10006.2} = <em>56.4 m</em>

3 0
4 years ago
What are the chemical symbols of the particles found in the calcium chloride crystal (lattice)​
Alinara [238K]

Answer:

Formula and structure: The chemical formula of calcium chloride is CaCl2, and its molar mass is 110.983 g/mol. It is an ionic compound consisting of the calcium cation (Ca2+) and two chlorine anions (Cl-). The bivalent calcium metal forms an ionic bond with two chlorine atoms, as shown below.

6 0
3 years ago
In an experiment, 12.0dm3 of oxygen, measured under room conditions, is used to burn completely 0.10mol of propan-1-ol. What is
Ksju [112]
2C₃H₇OH + 9O₂ = 6CO₂ + 8H₂O

V(O₂)=12.0 dm³
n(C₃H₇OH)=0.1 mol

n(O₂)=12.0 dm³/22.4 dm³/mol=0.5357 mol

C₃H₇OH : O₂   2:9    1:4.5

0.1:0.5357
oxygen in excess

V(CO₂)=3Vm*n(C₃H₇OH)

V(CO₂)=3*22.4*0.1=6.72 dm³

5 0
3 years ago
Read 2 more answers
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