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Alexus [3.1K]
2 years ago
9

One significant difference between gases and liquids is that:

Chemistry
1 answer:
erma4kov [3.2K]2 years ago
7 0

Answer:

A

Explanation:

all the other answers are wrong or not applicable. hope this helps :)

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Help please ill do anything really!!!!!!!
Volgvan

Answer:

The first one is air the second is decreases the third is water the fourth is gas and the last is liquid.

Explanation:

Hope it helps.

5 0
2 years ago
*multiple choice*
galben [10]

1.95  or 2  is the molarity of a 45.3g sample of KNO3 (101g) dissolved in enough water to make a 0.225L solution.

The correct answer is option b

Explanation:

Data given:

mass of KNO_{3} = 45.3 grams

volume = 0.225 litre

molarity =?

atomic mass of KNO3 = 101 grams/mole

molarity is calculated by using the formula:

molarity = \frac{number of moles}{volume of the solution}

first the number of moles present in the given mass is calculated as:

number of moles = \frac{mass}{atomic mass of 1 mole}

number of moles = \frac{45.3}{101}

0.44 moles of KNO3

Putting the values in the equation of molarity:

molarity = \frac{0.44}{0.225}

molarity = 1.95

It can be taken as 2.

The molarity of the potassium nitrate solution is 2.

7 0
2 years ago
Is it possible for a balloon with an initial internal pressure equal to 250.0 kPa
MrRa [10]
No, don't try, it will explode  close to 187 kPa
6 0
3 years ago
a square boat made from iron has overall dimensions of 2.00 cm x 11.0 cm x 11.0 cm. it has a mass of 213 g. water has a density
Stolb23 [73]
Density of boat  =  \frac{MASS}{VOLUME}
                           
                          =  \frac{213 g}{(2 cm  *  11 cm  *  11cm)}
 
                          =   0.88 g / cm³

Since the density of water is greater than the density of the boat ( 1 > 0.88) then that means, the boat will NOT sink.

B.

4 0
3 years ago
Read 2 more answers
Michelle is trying to find the average atomic mass of a sample of an unknown
GREYUIT [131]

The average atomic mass of her sample is 114.54 amu

Let the 1st isotope be A

Let the 2nd isotope be B

From the question given above, the following data were obtained:

  • Abundance of isotope A (A%) = 59.34%
  • Mass of isotope A = 113.6459 amu
  • Mass of isotope B = 115.8488 amu
  • Abundance of isotope B (B%) = 100 – 59.34 = 40.66%
  • Average atomic mass =?

The average atomic mass of the sample can be obtained as follow:

Average \: atomic \: mass \:  =  \frac{mass \: of \: A \times A\%}{100}  + \frac{mass \: of \: B \times B\%}{100}  \\  \\ Average \: atomic \: mass \:  =  \frac{113.6459\times 59.34}{100} + \frac{115.8488\times 40.66}{100} \\  \\ Average \: atomic \: mass \:  = 114.54 \: amu  \\  \\

Thus, the average atomic mass of the sample is 114.54 amu

Learn more about isotope: brainly.com/question/25868336

3 0
2 years ago
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