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Liono4ka [1.6K]
3 years ago
6

How many inches are in 2\1 2 feet?

Mathematics
2 answers:
FrozenT [24]3 years ago
5 0

Answer:

30 inches

Step-by-step explanation:

2(12) 24

2(6) 6

24in plus 6in = 30in

mamaluj [8]3 years ago
3 0

Answer:

30 inches

Step-by-step explanation:

1 ft= 12 inches

12×2= 24

1/2 of 12 is 6

24+6=30

30 inches

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8 divided by (7 - 3) x ( 4 + 6)<br> Equals?
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8÷(7-3)x(4+6)

8÷4x10

2x10

<u>20</u>

3 0
3 years ago
What is the sum or whatever of this equation. This equation is V = πx3^2x8
navik [9.2K]

Answer:

V=226.08

Step-by-step explanation:

To evaluate V from the following expression:

V=\pi\times3^2\times 8

Taking \pi=3.14

V=3.14\times 3^2\times 8

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6 0
3 years ago
Find the length of the third side. If necessary, write in simplest radical form.
Angelina_Jolie [31]

Answer:

the length of the missing side is 2

Step-by-step explanation:

Use a^2 + b^2 = c^2

a = 4

b = ?

c = 2sqrt5

4^2 + b^2 = (2sqrt5)^2

16 + b^2 = 20

subtract 16 from both sides

b^2 = 4

take the sqrt of both sides

b = 2

3 0
2 years ago
Read 2 more answers
To test the belief that sons are taller than their​ fathers, a student randomly selects 13 fathers who have adult male children.
KATRIN_1 [288]

Answer:

1) B. The differences are normally distributed or the sample size is large

C. The  sample size mus be large

E. The sampling method results in an independent sample

2) The null hypothesis H₀:  \bar x_1 =  \bar x_2

The alternative hypothesis Hₐ: \bar x_1 <  \bar x_2

Test statistic, t = -0.00693

p- value = 0.498

Do not reject Upper H₀ because, the P-value is greater than the level of significance. There is sufficient evidence to conclude that sons are the same height as their fathers  at 0.10 level of significance

Step-by-step explanation:

1) B. The differences are normally distributed or the sample size is large

C. The  sample size mus be large

E. The sampling method results in an independent sample

2) The null hypothesis H₀:  \bar x_1 =  \bar x_2

The alternative hypothesis Hₐ: \bar x_1 <  \bar x_2

The test statistic for t test is;

t=\dfrac{(\bar{x}_1-\bar{x}_2)}{\sqrt{\dfrac{s_{1}^{2} }{n_{1}}-\dfrac{s _{2}^{2}}{n_{2}}}}

The mean

Height of Father, h₁,  Height of Son h₂

72.4,      77.5

70.6,      74.1

73.1,       75.6

69.9,      71.7

69.4,      70.5

69.4,      69.9

68.1,       68.2

68.9,      68.2

70.5,       69.3

69.4,       67.7

69.5,       67

67.2,       63.7

70.4,       65.5

\bar x_1  = 69.6      

s₁ = 1.58

\bar x_2 = 69.9

s₂ = 3.97

n₁ = 13

n₂ = 13

t=\dfrac{(69.908-69.915)}{\sqrt{\dfrac{3.97^{2}}{13}-\dfrac{1.58^{2} }{13}}}

(We reversed the values in the square root of the denominator therefore, the sign reversal)

t = -0.00693

p- value = 0.498 by graphing calculator function

P-value > α Therefore, we do not reject the null hypothesis

Do not reject Upper H₀ because, the P-value is greater than the level of significance. There is sufficient evidence to conclude that sons are the same height as their fathers  at 0.10 lvel of significance

8 0
4 years ago
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