Answer:
Step-by-step explanation:
We are given that:
Where <em>A</em> is in QI.
And we want to find sec(A).
Recall that cosecant is the ratio of the hypotenuse to the opposite side. So, find the adjacent side using the Pythagorean Theorem:
So, with respect to <em>A</em>, our adjacent side is 63, our opposite side is 16, and our hypotenuse is 65.
Since <em>A</em> is in QI, all of our trigonometric ratios will be positive.
Secant is the ratio of the hypotenuse to the adjacent. Hence:
Answer:
the place value
Step-by-step explanation:
you should place similar place values in one line
The average rate of change of a (continuous) function f(x) over an interval [a, b] is given by the so-called difference quotient,
Here we have f(x) = x² + 8x + 12 and the interval is [-10, -2], so the ARoC of f(x) on this interval is
Hi there
annual premium
7,000÷10years=700 per year
quarterly premium
Quarterly means 4 times a year so
7,000÷(4×10)=175 per quarter
difference between them
700−175=525
Good luck!
Answer:
- -2^x
- (1/3)^x +5
- 3^(x +2) -3
- (1/2)^x -2
- 4^(x/3)
- 2^(x -3) +4
Step-by-step explanation:
In general, the transformation ...
g(x) = f(x -h) +k
translates f(x) right h units and up k units.
The transformation ...
g(x) = f(x/a)
stretches the graph horizontally by a factor of "a".
The transformation ...
g(x) = -f(x)
causes the graph to be reflected over the x-axis.
___
Applying the above, we have ...
f(x) = 2^x reflected over x is g(x) = -2^x
f(x) = (1/3)^x translated up 5 is g(x) = (1/3)^x +5
f(x) = 3^x translated by (-2, -3) is g(x) = 3^(x +2) -3
f(x) = (1/2)^x translated down 2 is g(x) = (1/2)^x -2
f(x) = 4^x stretched horizontally by a factor of 3 is g(x) = 4^(x/3)
f(x) = 2^x translated by (3, 4) is g(x) = 2^(x -3) +4
