First, let's find the time where the ship arrives to point C
t=d/V, t= 45/30=1.5h
if the ship's departure time is at 1.5h, on the point C, let 's find its arrival to the point O, V=D/Dt, Dt=tfinal-tinitial
Dt=D/V= 20/30=0.6h=t final -t initial, implies t final=0.6+t initial=0.6+1.5=2.1h
so the ship will be on the radar at 2.1h,
Answer:
3 1/6
Step-by-step explanation:
Answer:
I think C i could be wrong tho
Step-by-step explanation:
2.4 because you divide 40 by 17. You get 2.352941176<span> and the 5 tells the 3 to go up so your answer is 2.4</span>
