Answer:
The correct answer is B. Contain generalizations and contractions.
Step-by-step explanation:
A generalization occurs when a specific idea is applied to a general category, in simple terms it occurs if a person states something always occur because this person saw it once. In this case, generalization occurs as this person affirms all stars are too far away and thus it will take a long time to get to those stars, however not all stars are as far away as this person believes and this does not mean it will take a long time to get there as new technology can be created, thus, this statement is not true and need revision. On the other hand, contractions refers to the process of shortening words by putting them together, this can be seen in "couldn't" ( could + not) and "they're" (they + are), contradictions are not correct as they should not be used in formal language and be avoided, thus, contradictions also need to be revised.
Answer:
{a , c}
Step-by-step explanation:
first find u intersection p
n(U n P ) = {a , b , c , d} n {b , d , e}
={d , b}
intersection means element or values which lies in both the sets
now to find p complement
note : p( bar at the top ) is read as p complement
p complement = n(U) - n(U n P)
={a , b , c , d} - {d , b}
={a , c}
n(U) -n(U n P) means the elements which is only in n(U ) but not in n(U n P)
Answer: β ≠ ±1
Step-by-step explanation: For a system of equations to have an unique solution, its determinant must be different from 0: det |A| ≠ 0. So,
det ![\left[\begin{array}{ccc}1&\beta&1-\beta\\2&2&0\\2-2\beta&4&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26%5Cbeta%261-%5Cbeta%5C%5C2%262%260%5C%5C2-2%5Cbeta%264%260%5Cend%7Barray%7D%5Cright%5D)
≠ 0
Determinant of a 3x3 matrix is calculated by:
det ![\left[\begin{array}{ccc}1&\beta&1-\beta\\2&2&0\\2-2\beta&4&0\end{array}\right]\left[\begin{array}{ccc}1&\beta\\2&2\\2-2\beta&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26%5Cbeta%261-%5Cbeta%5C%5C2%262%260%5C%5C2-2%5Cbeta%264%260%5Cend%7Barray%7D%5Cright%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26%5Cbeta%5C%5C2%262%5C%5C2-2%5Cbeta%264%5Cend%7Barray%7D%5Cright%5D)
![8(1-\beta)-[2(2-2\beta)(1-\beta)]](https://tex.z-dn.net/?f=8%281-%5Cbeta%29-%5B2%282-2%5Cbeta%29%281-%5Cbeta%29%5D)
β ≠ ±1
For the system to have only one solution, β ≠ 1 or β ≠ -1.
Answer:
C. 666
Step-by-step explanation:
USING PEMDAS we can solve this problem.
Answer:
£1,330.46
Hope this helps, mate!
Step-by-step explanation:
Hope this helps, mate! :)
