Answer:
A rectangular garden has dimensions of 19 feet by 16 feet. A gravel path of equal width is to be built around the garden. How wide can the path be if there is enough gravel for 246 square feet?
OA 5ft
OB. 3 ft
OC. 41
OD. 5.5 ft
Y = x^2 + 10x - 171
y = (x - 9)(x + 19)
x - 9= 0 x + 19 = 0
x = 9 x = -19
Answer B covers all requirements... the factored form is
<span>y= (x + 19)(x - 9) </span>
<span>and the zeros are -19 and 9</span>
Answer:
9,999,995
Step-by-step explanation:
Answer:
w=10
L=50
Step-by-step explanation:
<h2><em>Length=5w</em></h2><h2><em>Width=W</em></h2>
6w=60
---- ----
6 6
w=10
5(10)=50
L=50
Also can you make me the top answer?
