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AveGali [126]
3 years ago
12

Solve for X Please walk me through the steps, I understand most of it I just forgot how to do it

Mathematics
1 answer:
nadya68 [22]3 years ago
8 0

Answer:

x=8

Step-by-step explanation:

first you need to find the unknown corner so you do 180-71= 109

then find the interior angle degree (n-2)*180 (n=number of sides) so (4-2)*180=2(180)=360

then set everything equal to 360:

10x+6+13x-2+8x-1+109=360

(combine like terms)

31x+112=360

(subtract 112 form both sides)

31x=248

(divide both sides by 31)

x=8

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{(-7, 200). (3.5). (0.5). (-2.0). (6.4), (-6. -9), (4,4}<br> Is this function or not function
Akimi4 [234]

Answer:

Not function

Step-by-step explanation:

I think this is not function because if the x value has same numbers then its not a function. :)

7 0
3 years ago
A
Lemur [1.5K]

Answer:

x + 6

Step-by-step explanation:

consider the x- coordinates of the right angle

x- coordinate of A = - 4

x- coordinate of B = 2

then

| 2 - (- 4) | = | 2 + 4 | = | 6 | = 6

the x- coordinate has been shifted 6 units to the right , so the rule is

x + 6

5 0
2 years ago
A school band sold 30 raffle tickets. Each ticket is labeled with a number from 1 to 30. One winning ticket will be drawn. What
MAVERICK [17]
4/15 is the answer to this question

3 0
3 years ago
Convert the following sum into a product. cosx + cos3x + cos5x + cos7x
kvv77 [185]

Answer:

4\cos x\cos (4x)\cos (2x)

Step-by-step explanation:

Given: cosx + cos3x + cos5x + cos7x

To convert: the given sum into product

Solution:

Use formula: \cos A+\cos B=2\cos \left ( \frac{A+B}{2} \right )\cos \left ( \frac{A-B}{2} \right )

cosx + cos3x + cos5x + cos7x=2\cos \left ( \frac{x+3x}{2} \right )\cos \left ( \frac{x-3x}{2} \right )+2\cos \left ( \frac{5x+7x}{2} \right )\cos \left ( \frac{5x-7x}{2} \right )\\=2\cos (2x)\cos (-x)+2\cos (6x)\cos (-x)\\=2\cos (2x)\cos (x)+2\cos (6x)\cos (x)\\=2\cos x\left [ \cos (2x)+\cos (6x) \right ]

cosx + cos3x + cos5x + cos7x=2\cos \left ( \frac{x+3x}{2} \right )\cos \left ( \frac{x-3x}{2} \right )+2\cos \left ( \frac{5x+7x}{2} \right )\cos \left ( \frac{5x-7x}{2} \right )\\=2\cos x\left [ \cos (2x)+\cos (6x) \right ]\\=2\cos x\left [2 \cos \left ( \frac{2x+6x}{2} \right )\cos \left ( \frac{2x-6x}{2} \right ) \right ]\\=2\cos x\left [ 2\cos (4x) \cos (-2x) \right ]\\=4\cos x\cos (4x)\cos (2x)

4 0
3 years ago
For which value of x does f(x) = 2
laila [671]

Answer:

<h2>x = -4</h2>

Step-by-step explanation:

<em>Look a the picture</em>.

Draw the horizontal line <em>y = 2</em>.

Common point: (-4, 2).

Conclusion: f(x) = 2 → x = -4

8 0
3 years ago
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