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Mars2501 [29]
2 years ago
8

Plz g0ive me solution

Mathematics
1 answer:
Serga [27]2 years ago
8 0

Answer:

separate the x from the numbers it will make the equation easier

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- If you divide a number by four and then add six, you<br> get eighteen. What is the number?
stiks02 [169]

Answer:

48

Step-by-step explanation:

Create an equation to represent this, where x is the unknown number.

\frac{x}{4} + 6 = 18

Solve for x, by first subtracting 6 from both sides:

\frac{x}{4} = 12

Multiply each side by 4:

x = 48

So, the number is 48

8 0
3 years ago
Read 2 more answers
Suppose that a, b \in \mathbb{Z}a,b∈Z, not both 00, and let d=\gcd(a, b)d=gcd(a,b). Bezout's theorem states that dd can be writt
lara [203]

Answer:

Step-by-step explanation:

Recall that we say that d | a if there exists an integer k for which a = dk. So, let d = gcd(a,b) and let x, y be integers. Let t = ax+by.

We know that d | a, d | b so there exists integers k,m such that a = kd and b = md. Then,

t = ax+by = (kd)x+(md)y = d(kx+my). Recall that since k,  x, m, y are integers, then (kx+my) is also an integer. This proves that d | t.

3 0
3 years ago
Answer qn in attachment​
leva [86]

Answer:

\implies \dfrac{ -4x+7}{2(x-2) }

Step-by-step explanation:

The given expression to us is ,

\implies \dfrac{\frac{ 3}{x-1} -4 }{ 2 -\frac{2}{x-1}}

Now take the LCM as ( x - 1 ) and Simplify , we have ,

\implies \dfrac{\frac{ 3 -4(x-1) }{x-1} }{ \frac{2-2(2x-1)}{x-1}}

Simplifying further , we get ,

\implies \dfrac{ -4x+7}{2(x-2) }

Hence the second option is correct .

4 0
3 years ago
Do I solve this by equaling both equations to each other?
Mars2501 [29]
Yes, you got it! You would need to set the equations equal to each other, because that represents when their populations are the same. Then, solving for x will find the time in months until you reach that equilibrium in population. If you need help solving for x, just comment on this. Hope it helps!
8 0
3 years ago
Help will give Brainly points
Eduardwww [97]
D is the right answer
6 0
2 years ago
Read 2 more answers
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