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kondaur [170]
2 years ago
10

Consumer products are required by law to contain at least as much as the amount printed on the package. For example, a bag of po

tato chips that is labeled as 10 ounces should contain at least 10 ounces.Assume that the standard deviation of the packaging equipment yields a bag weight standard deviation of 0.2 ounces. Assume the bag weight distribution is bell-shaped. Determine what average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag.
Mathematics
1 answer:
Troyanec [42]2 years ago
5 0

Answer:

The average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802

Step-by-step explanation:

We are given that

Standard deviation, \sigma=0.2ounces

We have to find the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag.

P(x\geq 10)=0.99

Assume the bag weight distribution is bell-shaped

Therefore,

P(\frac{x-\mu}{\sigma}\geq 10)=0.99

We know that

z=\frac{x-\mu}{\sigma}

Using the value of z

Now,

\frac{10-\mu}{0.2}=0.99

10-\mu=0.99\times 0.2

\mu=10-0.99\times 0.2

\mu=9.802

Hence, the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802

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