$\cfrac{a}{sinA}= \cfrac{b}{sinB} \ \ \to \\ sinB= \cfrac{b*sinA}{a} = \cfrac{14*sin35^o}{12}= 0.6692 \ \ \to \ m \angle B=42^o \\ \\ \\ m \angle C=180- m \angle A- m \angle B=180-35-42=103^o \\ \\ \\ \cfrac{a}{sinA}= \cfrac{c}{sinC} \ \ \to \ c= \cfrac{a*sinC}{sinA}= \cfrac{12*sin103^o}{sin35^o} \approx 20.4$

6 0

3 years ago

Please help i don't know how to do this

GaryK [48]

Step-by-step explanation:

y = (x - 4)/x = x/x - 4/x = 1 - 4/x

c = 1

r = -4

done ...

6 0

2 years ago

Câu 4.19 . Vi phân cấp hai của hàm L ( x ; y )

laila [671]

Answer:

hi i dont understan hahahag

6 0

2 years ago

Find the inverse of the function:<br> y=log₂(-4x)

Vlad1618 [11]

Answer:

-2^(x-2)

Step-by-step explanation:

Using differential calculus:

We know that the integral of 1/x = ln(x)

or 2x/ln(2) = log2(x), so we plug in our knowledge and chain rule to figure out that the answer to the inverse is -2^(x-2) :)

5 0

3 years ago