What is the y-intercept of y = -3x

If the null space of a 5 × 8 matrix A is 4-dimensional, what is the dimension of the column space of A? dim Col A-(Simplify your

Eva8 [605]

Answer: Dim Col A = 4.

Step-by-step explanation:

Since we have given that

Matrix A has 5 rows and 8 columns.

And Nul A = 4

It implies that the rank of A would be

Number of columns - Nul A = 8 - 4 =4

So, rank A = 4

so, it has dim Col A = 4 also.

But the four vector basis lie in R⁵.

Hence, Dim Col A = 4.

5 0

2 years ago

My question that I need help on

horsena [70]

Answer:

Step-by-step explanation:

7 0

2 years ago

What is the area of this triangle?

Georgia [21]

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Formula:
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Area of triangle = 1/2 ab sin c

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Find area
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Area of triangle = 1/2 (13) (7.5) sin (94)
Area of triangle = 48.6 in² (nearest tenth)

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Answer: Area of triangle = 48.6 in²
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6 0

2 years ago

Read 2 more answers

A newspaper stand sold 1,000 copies of the city newspaper for $1,600 write and solve an equation to find the price of one copy

Vsevolod [243]

Answer: $\$1.6$

Step-by-step explanation:

Let be "x" the price in dollars of one copy of the city newspaper.

You need to analize the information provided in the exercise:

1. The total number of copies of the city newspaper sold in the newspaper stand is:

$Total\ copies=1,000$

2. The amount of money earned by selling 1,000 copies of the city newspaper is:

$Total\ earned=\$1,600$

Then, you can determine that the value of "x" can be found with:

$x=\frac{Total\ earned}{Total\ copies}$

3. Finally, substituting values, you get:

$x=\frac{\$1,600}{1,000}\\\\x=\$1.6$

7 0

2 years ago

Pls help these are my teachers instructions

Yanka [14]

The mistake he did, was in calculating powers, when 12 is taken to numerator it becomes -12 and 6-12 is -6 and not 6 so power of x should be -6 i.e x^-6 and not x^6

So, the correct answer is $=\frac{27}{4x^{6}y^{8}}$

Step-by-step explanation:

We need to simplify:

$\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$

Solving:

$\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$

Multiplying power with the terms inside the bracket.

$=\frac{4(3^3x^6y^{12})}{2^4x^{12}y^{20}}\\=\frac{4(27x^6y^{12})}{16x^{12}y^{20}}\\=\frac{108x^6y^{12}}{16x^{12}y^{20}}$

Now combining powers of same variable i.e if $\frac{x^a}{x^b}=x^{a-b}$

Solving:

$=\frac{108x^{6-12}y^{12-20}}{16}\\=\frac{108x^{-6}y^{-8}}{16}\\Divide\,\,by\,\,4:\\=\frac{27x^{-6}y^{-8}}{4}$

The exponent rule says: if $x^{-1} \,\,then\,\, \frac{1}{x}$

$=\frac{27}{4x^{6}y^{8}}$

The mistake he did, was in calculating powers, when 12 is taken to numerator it becomes -12 and 6-12 is -6 and not 6 so power of x should be -6 i.e x^-6 and not x^6

So, the correct answer is $=\frac{27}{4x^{6}y^{8}}$

Keywords: Exponents

Learn more about Exponents at:

#learnwithBrainly

3 0

2 years ago