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Vladimir [108]
2 years ago
12

S(t)=sqrt3t+1 at t=2

Mathematics
1 answer:
avanturin [10]2 years ago
5 0

Answer:

s(2) = √7

Step-by-step explanation:

s(2) = √(3[2] + 1) = √7

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?...............................
arsen [322]

Answer:

-2 ≤ n < 8

Step-by-step explanation:

_________________

5 0
3 years ago
Double time pay is twice the regular time pay rate. If Rita, a nurse, earns $24 per hour for her regular pay rate and she is pai
Kitty [74]

Answer:24r+48h= $1248

Step-by-step explanation:

24*36+48*8

864 + 384 = 1248

Not sure if it's correct I'm not brilliant with equations xx

8 0
3 years ago
Which relation is a function of x?<br> 1 {(1,2), (7, 6), (3, 2), (1, 0), (5, 6)}. <br> 3. x=3y²–7
avanturin [10]

9514 1404 393

Answer:

  The given graph shows a function of x.

Step-by-step explanation:

Neither 1 nor 3 is a single-valued relation for some values of x. The graph shown passes the vertical line test, so does represent a function.

The graph is a relation that is a function of x.

___

The attached graph is of the equation of 3. A vertical line will intersect the graph in more than one place, so the relation is NOT a function.

4 0
2 years ago
Offering 40 points and brainliest for answer
Nata [24]
In fact, this problem belongs to the chemistry section.  Recall that many other sciences require mathematical calculations.  The problem will belong to Mathematics only if no knowledge of other sciences are required to solve the problem.

Solubility for the given substances is measured in grams per 100 g of water at a particular temperature (20 deg.C).
This means that the mass (assumed to be the solute) will not change the solubility, just the minimum quantity of solvent (water) will.
Thus the solubility of sodium chloride will remain L=36 g/100g H2O for any quantity of solute.  Similarly, the solubility of lead nitrate will remain as K=54 g/100 g H2O.

The reason that they remain constant is because the quantity of solvent (water) is fixed at 100 g.  Varying amount of solute will affect the quantity of solvent required, but not the solubility.
I'll leave it to you to calculate the difference between K & L.
8 0
2 years ago
Negative one fourths times negative six elevenths
Ipatiy [6.2K]

You multiply fractions simply by multiplying numerators and denominators with each other:

-\dfrac{1}{4} \times \left(-\dfrac{6}{11}\right) = \dfrac{1 \times 6}{4 \times 11} = \dfrac{6}{44} = \dfrac{3}{22}

3 0
3 years ago
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