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Alexeev081 [22]
2 years ago
5

Helppppppppp I can’t do math

Mathematics
1 answer:
saw5 [17]2 years ago
4 0

Answer:

i believe its C

Step-by-step explanation:

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Let φ(x, y) = arctan (y/x) .
Alexandra [31]

Answer:

a) \large F(x,y)=(-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})

b) \large \mathbb{R}^2-\{(0,0)\}

c) the points of the form (x, -x) for x≠0

Step-by-step explanation:

a)

If φ(x, y) = arctan (y/x), the vector field F = ∇φ would be

\large F(x,y)=(\frac{\partial \phi}{\partial x},\frac{\partial \phi}{\partial y})

On one hand we have,

\large \frac{\partial \phi}{\partial x}=\frac{\partial arctan(y/x)}{\partial x}=\frac{-y/x^2}{1+(y/x)^2}=-\frac{y/x^2}{1+y^2/x^2}=\\\\=-\frac{y/x^2}{(x^2+y^2)/x^2}=-\frac{y}{x^2+y^2}

On the other hand,

\large \frac{\partial \phi}{\partial y}=\frac{\partial arctan(y/x)}{\partial y}=\frac{1/x}{1+(y/x)^2}=\frac{1/x}{1+y^2/x^2}=\\\\=\frac{1/x}{(x^2+y^2)/x^2}=\frac{x}{x^2+y^2}

So

\large F(x,y)=(-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})

b)

The domain of definition of F is  

\large \mathbb{R}^2-\{(0,0)\}

i.e., all the plane X-Y except the (0,0)

c)

Here we want to find all the points such that

\large (-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})=(k,k)

where k is a real number other than 0.

But this means

\large -\frac{y}{x^2+y^2}=\frac{x}{x^2+y^2}\Rightarrow y=-x

So, all the points in the line y = -x except (0,0) are parallel to the vector field F, that is, the points (x, -x) with x≠ 0

8 0
2 years ago
I need help please and thank you!!!!
Naddika [18.5K]

Answer:

Bottom left graph.

Step-by-step explanation:

I answered this by finding the y-int.

8(0) - 3y = 18

-3y = 18

y = -6

And it has a positive relationship so the line slants from bottom left to top right.

4 0
3 years ago
Write an equation in slope-intercept form for the graph shown.
worty [1.4K]

Answer:

The equation of the graph in slope-intercept form is y = 3x + 7. 2. slope-intercept form is y = x + 2.

7 0
2 years ago
Read 2 more answers
Question: Antonio is working with a new geometric series generated by the equation A(n)=20(1.1)^n-1.His sister challenged him to
Mekhanik [1.2K]

Answer:

sum of 22nd = 1,428.05

sum of 23 to 40 is 932.53

Step-by-step explanation:

A(n)=20(1.1)^n-1

20 is the first term or a1

1.1 is the common ratio or r

A(22) = 20(1.1)^22-1

22nd term = 20(1.1)^21

22nd term = 148.00

sum of geometric sequence

formula

Sn = a1(1-r^n)/1-r

Sn = sum

a1 = first term

n = number of term

r = constant ratio

sum of 22nd = 1,428.05.

23 to 40 is 17 terms

Sequence: 23, 25.3, 27.83, 30.613, 33.6743, 37.04173, 40.745903 ...

The 17th term: 105.684378686

Sum of the first 17 terms: 932.528165548

socratic

miniwebtoolcomgeometricsequencecalculator

6 0
2 years ago
HELP ASAP PLEASE THX..........................??????
otez555 [7]
Positive product:
(-2/5)(-2/5)
(2/5)(2/5)

negative product:
(-2/5)(2/5)
(2/5)(-2/5)

6 0
3 years ago
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