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Molodets [167]
2 years ago
6

How to solve this problem!

Mathematics
1 answer:
adell [148]2 years ago
8 0
You really have 2 separate equations to solve here:

1) 5(x-1) = - 20        =>     5x - 5 = -20 =>  5x = -15      => x = -3
2) 3y = -15     => y = -5
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I need help solving |5+2j|=9 please
V125BC [204]

5 + 2j = 9 \\ j = 2
5 + 2j =  - 9 \\ j =  - 7
3 0
2 years ago
Can a cubic equation have 3 complex roots? 3 real roots? ...?
trasher [3.6K]
No, a cubic equation can not have three complex roots. This is because it turns twice and one end goes to positive infinity and one end goes to negative infinity. Thus, one of these MUST cross the x-axis at some point, meaning y = 0 and a real root exists.

Yes, a cubic equation can have three real roots if it cuts the x-axis three times.
7 0
3 years ago
Can SOMEONE HELP ME with this PLEASE!!!!
makkiz [27]

Answer:

12.4

Step-by-step explanation:

The distance between (7,21) and (-5,18)

d =sqrt( (-5-7)^2 + (18-21)^2)

  = sqrt(( -12)^2 + (-3)^2)

  = sqrt(144+9)

  = sqrt(153)

  =12.36931688

To the nearest tenth

12.4

6 0
2 years ago
Consider a collection of envelopes consisting of 1 red envelope, 3 blue envelopes, 2 green envelopes, and 3 yellow envelopes if
nasty-shy [4]

Answer:

the probability that at least one envelope is a yellow envelope is 16/21

Step-by-step explanation:

The probability that at least one envelope is a yellow envelope is P(Y);

P(Y) = 1 - P(Y)'

P(Y)' is the probability that no envelope is a yellow envelope.

Given;

red envelope = 1

blue envelopes = 3

green envelopes = 2

yellow envelopes = 3

Total = 9

Number of non-yellow envelope = 9 -3 = 6

(6 envelope are not yellow)

P(Y)' = P1 × P2 × P3

Since there is no replacement;

P(Y)' = 6/9 × 5/8 × 4/7

P(Y)' = 5/21

From equation 1;

P(Y) = 1 - 5/21

P(Y) = 16/21

the probability that at least one envelope is a yellow envelope is 16/21.

8 0
3 years ago
Sam & Avery are making small and large birdhouses for a craft show. Small houses sell for $10 and large houses sell for $15.
Lemur [1.5K]

Answer:

  • 8 small houses; 0 large houses
  • 80 small houses; 0 large houses

Step-by-step explanation:

a) The maximum number of houses Sam can build in 24 hours is 8, so the constraint is in construction, not decoration. For each small house Sam constructs, he makes $10/3 = $3.33 per hour of work. For each large house Sam constructs, he makes $15/5 = $3.00 per hour. The most money is to be made by building only small houses.

Sam should make 8 small houses and 0 large houses in 24 hours.

__

b) If Sam works 8-hour days, then he can complete at most 80 small houses. The constraint remains in construction, so the answer is the same: build only small houses.

_____

If Sam works more than 16 2/3 hours per day, he can build 100 large houses or more, so the constraint moves to decoration. The decorator makes more money by decorating large houses, so all the effort should go to construction of large houses.

If Sam works between 10 and 16 2/3 hours per day, the best revenue will come from some mix. The problem statement is unclear as to how many hours Sam works in 30 days.

5 0
3 years ago
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