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3 years ago

How to solve this problem!

Mathematics

1 answer:

adell [148]3 years ago

8 0

You really have 2 separate equations to solve here:

1) 5(x-1) = - 20 => 5x - 5 = -20 => 5x = -15 => x = -3
2) 3y = -15 => y = -5

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Find the percent of the number. <br> 522% of 85

Ber [7]

If you would like to calculate 522% of 85, you can do this using the following steps:

522% of 85 = 522% * 85 = 522/100 * 85 = 443.7

The correct result would be 443.7.

6 0

3 years ago

Read 2 more answers

1/2 divided by 3 (im doing a quiz and im stuck lol(

Irina18 [472]

Answer:

Isn't it 1/6

Step-by-step explanation:

1 . 1

_ _ 3 = _

2 . 6

4 0

2 years ago

Read 2 more answers

700/200 in a terminating decimal

Aneli [31]

700/200=7/2 because devide by 100 and then=3 1/2 and half is .5 so= 3.5

8 0

3 years ago

2. Find the missing angle x.<br> 155°<br> 60°<br> X

Kryger [21]

Answer:

exterior angle property use ...

the exterior angle of an angle is equal to sum of rest 2 interior angles in a triangle

155 = 60 + x

x = 155 - 60 = 95

8 0

3 years ago

Please help?!

Anton [14]

Answer:

Δ PQT ~ Δ QRS .....{S-S-S test for similarity}...Proof is below.

Step-by-step explanation:

Given:

In Δ PQT

PQ = 30 ft

QT = 28 ft

TP = 20 ft

In Δ QRS

QR = 15 ft

RS = 14 ft

SQ = 10 ft

To Prove:

Δ PQT ~ Δ QRS

Proof:

First we consider the ratio of the sides

$\frac{PQ}{QR}=\frac{30}{15} = \frac{2}{1}$ ..............( 1 )

$\frac{QT}{RS}=\frac{28}{14} = \frac{2}{1}$ ..............( 2 )

$\frac{TP}{SQ}=\frac{20}{10} = \frac{2}{1}$ ..............( 3 )

So By equation ( 1 ), ( 2 ) and ( 3 ) we get

$\frac{PQ}{QR}=\frac{QT}{RS} = \frac{TP}{SQ}$

Now in Δ PQT and Δ QRS we have

$\frac{PQ}{QR}=\frac{QT}{RS} = \frac{TP}{SQ}$

Which are corresponding sides of a similar triangle in proportion.

∴ Δ PQT ~ Δ QRS .....{S-S-S test for similarity}...Proved

8 0

3 years ago