Answer:
z= 3.63
z for significance level = 0.05 is ± 1.645
Step-by-step explanation:
Here p = 42% = 0.42
n= 500
We formulate our null and alternative hypotheses as
H0: p= 0.42 against Ha : p> 0.42 One tailed test
From this we can find q which is equal to 1-p= 1-0.42 = 0.58
Taking p`= 0.5
Now using the z test
z= p`- p/ √p(1-p)/n
Putting the values
z= 0.5- 0.42/ √0.42*0.58/500
z= 0.5- 0.42/ 0.0220
z= 3.63
For one tailed test the value of z for significance level = 0.05 is ± 1.645
Since the calculated value does not fall in the critical region we reject our null hypothesis and accept the alternative hypothesis that more than 42% people owned cats.
Answer:
The answer is option D: the advertiser is bidding $0.70 between 9 pm-12 am on weeknights.
Step-by-step explanation:
The normal bid is $0.40 and the bid multiplier is 75%.
This amount becomes:

= $0.70 (OPTION D)
So, the advertiser is bidding $0.70 between 9 pm-12 am on weeknights.
Answer:
72 cubes
Step-by-step explanation:
Attached is the picture drawn (though not great one), showing 6 cube on length of prism, 3 cubes on width and 4 cubes on height of prism.
Given: Length of prism= 6
Width= 3
Height= 4
To know the number of cubes, which can fill the entire prism, we need to find volume of prism.
∴ Volume of prism= 
Volume of prism= 
∴ 72 units of cube can fill the entire prism.
well if you posted the graph i could give the exac answer but i cant so all you have to do is take one of the orignal points and move it down 5 units and left 8 units do that to all points and then you will have your answer