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enyata [817]
3 years ago
10

Which equation can be used to find the measure of the angles below if line a is parallel to line b?

Mathematics
2 answers:
dangina [55]3 years ago
6 0

Answer:

C. 5x - 54 = 3x + 16

Step-by-step explanation:

These angles are alternate interior angles and their measurement is same

5x - 54 = 3x + 16

5x - 3x = 16 + 54

2x = 70 divide both sides by 2

x = 35

IgorC [24]3 years ago
5 0
I think the answer is c
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Find the surface area of each prism
goldfiish [28.3K]

Answer:

Step-by-step explanation:

2.

Surface area = ( 6 *10 ) *3  + ( ( 7*4.87) /2)*2 = 180 + 34.09 = 214.09

3.

Surface area = (5*10) *3 + (( 7*4.2)/2)*2 = 150 +29.4 = 179.4

6 0
3 years ago
Translate each algebraic expression to a verbal phrase
GaryK [48]

Answer:

1.  A number decreased by seven.

2. A number increased by nine.

3. The product of six and a number, divided by eight.

4. The product of three and a number increased by five is equal to twenty.

5. The product of two and a number increased by eight is equal to twenty-three.

Step-by-step explanation:

1.   x-7

A number decreased by seven.

2. y+9

A number increased by nine.

3. 6m/8

The product of six and a number, divided by eight.

4. 3y+5 =20

The product of three and a number increased by five is equal to twenty.

5. 2(x+8)= 23

The product of two and a number increased by eight is equal to twenty-three.

3 0
2 years ago
Rearrange x = 7y - 5 to make y the subject.
nalin [4]

By rearranging x = 7y - 5 to make y the subject, we get

x + 5 = 7y ( By transposition method )

or, \huge \purple {\tt {\frac{x + 5}{7}  = y}}

<h2>Answer:</h2>

\huge \pink {\tt {y =  \frac{x + 5}{7}}}

3 0
3 years ago
The coordinates of rhombus ABCD are A(–4, –2), B(–2, 6), C(6, 8), and D(4, 0). What is the area of the rhombus? Round to the nea
a_sh-v [17]
Check the picture below.

so the rhombus has the diagonals of AC and BD, now keeping in mind that the diagonals bisect each, namely they cut each other in two equal halves, let's find the length of each.

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\bf ~~~~~~~~~~~~\textit{distance between 2 points}&#10;\\\\&#10;B(\stackrel{x_1}{-2}~,~\stackrel{y_1}{6})\qquad &#10;D(\stackrel{x_2}{4}~,~\stackrel{y_2}{0})\qquad \qquad BD=\sqrt{[4-(-2)]^2+[0-6]^2}&#10;\\\\\\&#10;BD=\sqrt{(4+2)^2+(-6)^2}\implies BD=\sqrt{6^2+6^2}&#10;\\\\\\&#10;BD=\sqrt{6^2(2)}\implies \boxed{BD=6\sqrt{2}}

that simply means that each triangle has a side that is half of 10√2 and another side that's half of 6√2.

namely, each triangle has a "base" of 3√2, and a "height" of 5√2, keeping in mind that all triangles are congruent, then their area is,

\bf \stackrel{\textit{area of the four congruent triangles}}{4\left[ \cfrac{1}{2}(3\sqrt{2})(5\sqrt{2}) \right]\implies 4\left[ \cfrac{1}{2}(15\cdot (\sqrt{2})^2) \right]}\implies 4\left[ \cfrac{1}{2}(15\cdot 2) \right]&#10;\\\\\\&#10;4[15]\implies 60

7 0
2 years ago
Read 2 more answers
Hey plsss help meeeeee
nalin [4]

Answer:

The first, third, and fourth answer choices represent a function.

Step-by-step explanation:

A relation is a relationship between sets of values. The two quantities that are being related to each other are the input (x-variable) and the output (y-variable). But relations in general aren't always a good way to relate between x and y.

Say that I have situation where I want to give <em>x </em>dollars to the cashier so he can change them to <em>y</em> quarters. Here is a "example" of the relation:

Dollars (x) | Quarters (y)            

----------------------------------              

       0       |          0                      

        1       |          4                      

       2       |          8

       2       |          12

Do you see something wrong here? Yes! We all know that you can't exchange 2 dollars for 12 quarters. You can only exchange 2 dollars for 8 quarters and only 8 quarters. This is a general reason why we don't rely on general relations for real-life situations. One x-variable does not exactly map to one and only one y-variable.

However, a relation that can map one x-variable to one and only one y-variable is known as a function. Let's make the above example an actual function to prove a point:

Dollars (x) | Quarters (y)            

----------------------------------              

       0       |          0                      

        1       |          4                      

       2       |          8

       3       |          12

Now, the 3 dollars make 12 quarters as it should. This is how a function should look like.

There are two ways to check if a relation is a function. On a relation, table, or a set of ordered pairs, you have to make sure there is no "x-variable" that repeats. All x-values of a relation have to be unique in order to be a function. On a graph, you can also perform the Vertical Line Test. If you draw vertical lines over a relation and if the lines cross only once, then it is a function. If not, it fails the Vertical Line Test.

So to answer you're question, the first, third, and fourth choices are functions because they all have unique x-variables. The second choice is not a function because it fails the Vertical Line Test.

7 0
2 years ago
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