Answer:
(-2, 2)
Step-by-step explanation:
<u>Given:</u>
- Point A is at (2, -8) and point C is at (-4, 7)
<u>Difference of coordinates:</u>
- Δx = 2 - (-4) = 6
- Δy = - 8 - 7 = - 15
<u>The ratio of AB to AC is 2:1. So:</u>
- AB = 2*AC/3 and BC = AC/3
<u>Then coordinates of point B should be 2/3 from the point A:</u>
- x = 2- 6*2/3 = 2 - 4 = -2
- y = - 8 - (-15)*2/3 = -8 + 10 = 2
So point B has coordinates of (-2, 2)
It would be 43.75% because
7÷16=0.4375
0.4375×100=43.75%
Answer:
x = 1/4
y = -1/2
z = 9/4
Step-by-step explanation:
Here we have a system of 3 equations with 3 variables:
4*x + 2*y + 1 = 1
2*x - y = 1
x + 3*y + z = 1
The first step to solve this, is to isolate one of the variables in one of the equations, let's isolate "y" in the second equation:
2*x - y = 1
2*x - 1 = y
Now that we have an expression equivalent to "y", we can replace this in the other two equations:
4*x + 2*(2*x - 1) + 1 = 1
x + 3*(2*x - 1) + z = 1
Now let's simplify these two equations:
8*x - 1 = 1
7*x - 3 + z = 1
Now, in the first equation we have only the variable x, so we can solve that equation to find the value of x:
8*x - 1 = 1
8*x = 1 + 1 = 2
x = 2/8 = 1/4
Now that we know the value of x, we can replace this in the other equation to find the value of z.
7*(1/4) -3 + z = 1
7/4 - 3 + z = 1
z = 1 + 3 - 7/4
z = 4 - 7/4
z = 16/4 - 7/4 = 9/4
z = 9/4
Now we can use the equation y = 2*x - 1 and the value of x to find the value of y:
y = 2*(1/4) - 1
y = 2/4 - 1
y = 1/2 - 1
y = -1/2
Then the solution is:
x = 1/4
y = -1/2
z = 9/4
While both a and c work the most likely answer that they want would be A because it represent the cents already and it shows all possible ways that those two values can be split among 1 dollar
The answer is simple to work out you do 3/8 + 1/3
but the denominators are different so you find the lowest common multiple in this case 24 .
the frection is now 9/24 + 8/24 this is 17/24
I changed the fraction by doing this 24(common multiple) divided by 8 (denominator) that's how I got it if you don't understand just ask me
