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Anna71 [15]
3 years ago
6

The bed of a pick up truck measures 4' x 8" to the nearest inch what is the length of the longest thin metal bar that will lie f

lat in the bed
Mathematics
1 answer:
Andru [333]3 years ago
6 0
Ok so what y ou want to do it to max space, lie it diagonally
use pythagoren theorem
first convert the units

4'=4 feet
8''=8 inches
convert to inches
4 feet times 12=48 inches

so
pythagorea theorem is
a^2+b^2=c^2
c=hypotonuse
a and b are legs
in a right triangle

8 and 48 are the legs
fidn hypotonuse

8^2+48^2=c^2
64+2304=c^2
2368=c^2
8√37=c
aprox
48.66=c
4 feet amd 0.66 inches
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Step-by-step explanation:

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The table shows the total number y (in billions) of U.S. movie admissions each year for x years. Use a graphing calculator to fi
wariber [46]

Answer:

By rounding up of the constant and coefficient terms, we have;

The line of best, fit is y = 1.23 + 3.46 × 10⁻²·x

Step-by-step explanation:

The table for the data on the number of movie admissions each year is presented as follows;

Year, x                                             {}                      Admission, y

0                                                      {}                         1.24

2                                                       {}                        1.26

4                                                      {}                         1.39

6                                                      {}                         1.47

8                                                      {}                         1.49

10                                                      {}                        1.57

Using a graphing calculator, we have that the line of best fit is given by the following equation;

y = 1.23047619048 + 3.45714285714 × 10⁻²·x

Which is approximately, y = 1.23 + 3.46 × 10⁻²·x

3 0
3 years ago
Can someone confirm this? is it correct?
EastWind [94]
<span>60 Sorry, but the value of 150 you entered is incorrect. So let's find the correct value. The first thing to do is determine how large the Jefferson High School parking lot was originally. You could do that by adding up the area of 3 regions. They would be a 75x300 ft rectangle, a 75x165 ft rectangle, and a 75x75 ft square. But I'm lazy and another way to calculate that area is take the area of the (300+75)x(165+75) ft square (the sum of the old parking lot plus the area covered by the school) and subtract 300x165 (the area of the school). So (300+75)x(165+75) - 300x165 = 375x240 - 300x165 = 90000 - 49500 = 40500 So the old parking lot covers 40500 square feet. Since we want to double the area, the area that we'll get from the expansion will also be 40500 square feet. So let's setup an equation for that: (375+x)(240+x)-90000 = 40500 The values of 375, 240, and 90000 were gotten from the length and width of the old area covered and one of the intermediate results we calculated when we figured out the area of the old parking lot. Let's expand the equation: (375+x)(240+x)-90000 = 40500 x^2 + 375x + 240x + 90000 - 90000 = 40500 x^2 + 615x = 40500 x^2 + 615x - 40500 = 0 Now we have a normal quadratic equation. Let's use the quadratic formula to find its roots. They are: -675 and 60. Obviously they didn't shrink the area by 675 feet in both dimensions, so we can toss that root out. And the value of 60 makes sense. So the old parking lot was expanded by 60 feet in both dimensions.</span>
8 0
3 years ago
Just some math :&gt; and meh needs halp
vesna_86 [32]

Answer:16

Step-by-step explanation:

5 times 2 is 10. 10 times 0 is 0. 1 times 6 is six

8 0
3 years ago
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