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deff fn [24]
2 years ago
8

What is the mass of an object if it takes a net force of 32 N to accelerate

Mathematics
1 answer:
Sonbull [250]2 years ago
5 0

We will find the answer using the second law of motion i.e. Force is equal to the product of mass and acceleration.

\sf \: F=ma

Where,

  • F is force
  • M is mass
  • A is acceleration

In our case,

  • F = 32 N
  • A = 0.88m/s
  • M = ?

Let's solve for M ~

\tt \: 32 = m \times 0.88

\tt \: 32 = 0.88m

\tt \: 0.88m = 32

\tt \: m = 36.36

<em>Thus, The mass of object is 36.36 </em><em>grams</em><em>.</em><em>.</em><em>.</em><em>~</em>

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4x + 5y = 12 and 3x + 4y = 9.25 . Solve for systems of equations
masha68 [24]

Answer:

y=1

x=7/4

Step-by-step explanation:

4x + 5y = 12

3x + 4y = 9.25

4x + 5y = 12

12x + 16y =37

-12x -15 y =-36

12x + 16y =37

y=1

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8 0
3 years ago
Read 2 more answers
What is the value of the following expression: w^2 + 2 + 48 divided by 2z. If w = 5 and z = 8
velikii [3]

Answer:

Replace w and z with the given values:

5^2 + 2 + 48 / 2(8)

Simplify:

75/16 = 4 and 11/16

Step-by-step explanation:

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3 years ago
A pan is heated to 393°F, then removed from the heat and allowed to cool in a kitchen where the room temperature is a constant 6
deff fn [24]

Answer:

The approximate temperature of the pan after it has been away from the heat for 9 minutes is 275.59°F.

Step-by-step explanation:

The formula for D, the difference in temperature between the pan and the room after t minutes is:

D = 324\cdot e^{-0.05t}

Compute the approximate difference in temperature between the pan and the room after 9 minutes as follows:

D = 324\cdot e^{-0.05t}

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Then the approximate temperature of the pan after it has been away from the heat for 9 minutes is:

D = P - R

206.59 = P - 69

P = 206.59 + 69

P = 275.59°F

Thus, the approximate temperature of the pan after it has been away from the heat for 9 minutes is 275.59°F.

6 0
3 years ago
A Food Marketing Institute found that 39% of households spend more than $125 a week on groceries. Assume the population proporti
Anuta_ua [19.1K]

Answer:

0.6210

Step-by-step explanation:

Given that a Food Marketing Institute found that 39% of households spend more than $125 a week on groceries

Sample size n =87

Sample proportion will follow a normal distribution with p =0.39

and standard error = \sqrt{\frac{0.39(1-0.39)}{87} } \\=0.0523

the probability that the sample proportion of households spending more than $125 a week is between 0.29 and 0.41

=P(0.29

There is 0.6210 probability that the sample proportion of households spending more than $125 a week is between 0.29 and 0.41

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4 years ago
Write a linear function that relates y to x <br><br> y=
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y=x-2

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2 years ago
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