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3 years ago

A square patio has an area of 200 ft.² how long is each side of the patio to the nearest 0.05

Mathematics

1 answer:

kicyunya [14]3 years ago

3 0

Answer: Square root of 200= 14.14ft

Hoped I Helped

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Which fraction is the largest 5/7 7/10 10/13 show how u worked out the answer

Ronch [10]

Answer:

$3.1/13$

Step-by-step explanation:

$1.5/7 =0.214286$

$2.7/10=0.27$

$3.1/13 =0.238462$

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3 years ago

Use benchmark fractions to compare 2/9 and 5/6. Part A Which of the following is a benchmark fraction Heather can use to compare

Dimas [21]

Answer:

Step-by-step explanation:

2/9 and 5/6 have a lcm of 30.

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3 years ago

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What is 7 devided by 215 and the reminder of it

miss Akunina [59]

30 with the remainder of 714

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3 years ago

What is the interquartile range of this data 0 5 10 15 20

timama [110]

The interquartile range (IQR) is 15.

To find the IQR, you must:
1) Find the median
2) Split the data set in two at the median.
3) Find the medians from both the groups you made in Step 2
4) Label the smaller one Quartile 1 and the larger one Quartile 3 (Hint: The median is Quartile 2)
5) Subtract: Quartile 3 - Quartile 1

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3 years ago

Identify the "inside function" u = f(x) and the "outside function" y = g(u). Then find dy/dx using the Chain Rule.

skad [1K]

DfLet $f(x)=\sec x$ and $g(x)=\sqrt x$ . Then

$y=\sec\sqrt x=\sec(g(x))=f(g(x))=f\circ g(x)$

By the chain rule,

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm du}\dfrac{\mathrm du}{\mathrm dx}$

where $u=g(x)=\sqrt x$ , so that $y=f(g(x))=f(u)=\sec u$ . We have

$\dfrac{\mathrm du}{\mathrm dx}=\dfrac1{2\sqrt x}$
$\dfrac{\mathrm d\sec u}{\mathrm du}=\sec u\tan u$

and so

$\dfrac{\mathrm dy}{\mathrm dx}=\sec u\tan u\dfrac{\mathrm dy}{\mathrm du}=\dfrac{\sec\sqrt x\,\tan\sqrt x}{2\sqrt x}$

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3 years ago