<span>The vertex of the parabola is the highest or lowest point of the graph.
</span><span>y=-4x^2+8x-12 = -4 (x^2 -2x +3)
Lets work with this now: </span>x^2 -2x +3
x^2 -2x +3 -> what is the closeset perfect square?
x^2 -2x +1 = (x-1)^2
So
x^2 -2x +3 = (x-1)^2 +2
Replacing to original
y=-4x^2+8x-12 = -4 (x^2 -2x +3) = -4 ((x-1)^2 +2) = -4 (x-1)^2 - 8
The min or max point is where the squared part = 0
So when x=1 , y= -4*0-8=-8
This will be the max of the parabola as there is - for the highest factor (-4x^2)
The max: x=1, y= -8
Answer:
question 1 is 300
and question 2 is 24
Step-by-step explanation:
Answer:
9?
Step-by-step explanation:
its c a l c u l a t o r timeee.
-3 * 7= 21
21 - 12= 9
so now how do you put 9 in the thousands place it's just in the ones place which won't make sense
Answer:
shusidvxxosbsbzbz
Step-by-step explanation:
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