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3 years ago

By selling 33m of cloth ,prabha gained the selling price 11 m.what is the gain percent

Mathematics

1 answer:

Rzqust [24]3 years ago

8 0

Answer:

The gain percent is 33.3 %

Step-by-step explanation:

Let the selling price of 1 m cloth is p.

Cost of 33 m = 33 p

gain = cost of 11 m = 11 p

The gain percentage is given by

$\frac{11 p}{33 p}\times 100\\\\= 33.3 %$

The gain percent is 33.3 %.

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What is the integer that makes the following subtraction sentence true:<br><br> 8 −? = –1

VashaNatasha [74]

8 - ? = -1. the missing number would be 9.

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3 years ago

The table below shows randy breuers height in inches leading into his teen years. The graph below displays a scatter plot of the

-Dominant- [34]

The least-square regression line has a slope of:

m=(nΣxy-ΣyΣx)/(nΣx²-ΣxΣx)

and a y-intercept of:

b=(Σy-mΣx)/n

In this case: n=7, Σxy=4899, Σy=391, Σx=85, Σx²=1153 so

m=(7(4899)-391*85)/(7(1153)-85*85))=1058/846

b=(391*846-85*1058)/(7*846)=34408/846

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y=1.25x+40.67

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3 years ago

Read 2 more answers

Can someone please explain to me the difference between SAS and SSS in Geometry when dealing with triangle proofs?

ANTONII [103]

Hello from MrBillDoesMath!

Answer: SAS = side - angle -side congruence

SSS = side - side - side congruence

Discussion :

In Plane Geometry, identical triangles are said to be "congruent". There are several ways, depending upon the information you have, to prove 2 triangles are congruent.

In one approach ("SSS") if you can show that 2 triangles have identical side lengths, then the triangles are congruent. (A triangle has 3 sides, hence "SSS" -- 3 S's; 3 sides, get it?)

In another approach ("SAS") if you can show that 2 sides, and the angle included between those sides, in one triangle are identical to the sides and included angle in another triangle, then the triangles are congruent

It's easier to understand this with a picture or diagram than in words. Please review the SSS, SAS picture in your textbook

Regards, MrB

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3 years ago

The core melt- down and explosions at the nuclear reactor in Chernobyl in 1986 released large amounts of strontium-90, which dec

elena-14-01-66 [18.8K]

If $S(t)$ is the amount of strontium-90 present in the area in year $t$ , and it decays at a rate of 2.5% per year, then

$S(t+1)=(1-0.025)S(t)=0.975S(t)$

Let $S(0)=s$ be the starting amount immediately after the nuclear reactor explodes. Then

$S(t+1)=0.975S(t)=0.975^2S(t-1)=0.975^3S(t-2)=\cdots=0.975^{t+1}S(0)$

or simply

$S(t)=0.975^ts$

So that after 50 years, the amount of strontium-90 that remains is approximately

$S(50)=0.975^{50}s\approx0.282s$

or about 28% of the original amount.

We can confirm this another way; recall the exponential decay formula,

$S(t)=se^{kt}$

where $t$ is measured in years. We're told that 2.5% of the starting amount $s$ decays after 1 year, so that

$0.975s=se^k\implies k=\ln0.975$

Then after 50 years, we have

$S(50)=se^{50k}\approx0.282s$

5 0

3 years ago

Un cono ha l'area laterale di 255 pigreco cm^2, l'apotema di 17 cm e pesa 900 pigreco g. Calcola il peso specifico del materiale

valkas [14]

Answer:

The specific weight is $1.5\frac{g}{cm^{3}}$

Step-by-step explanation:

The question in English

A cone has a lateral area of 255 pi cm^2, an apothem of 17 cm and weighs 900 pi g. It calculates the specific weight of the material of which it is composed

step 1

Find the radius of the cone

we know that

The lateral area of a cone is equal to

$LA=\pi rl$