Answer:
160 in ^2
Step-by-step explanation:
First we need to find the area of each shape and add them together
1. Triangles:
The formula for a triangle is (base x height)/2, so we can replace them as (5 * 4)/2 * 2( Because there are two triangles), so therefore the two triangles will add up to 20 inches
2. The Rectangles
<u>The Big Rectangle:</u>
The big rectangle is just <em>l x w </em> or 5 * 20 which is 100
<u>The small rectangle:</u>
To find the width of the small rectangle you have to do 20 - (5 + 5) because we are not including the triangles. 20 - (5 + 5) = 10, so that would be 10 * 4 = 40.
3.Add them together
20 + 100 + 40 = 160 inches ^2
Hope this helps!!!
Add n on both sides:
3m = km - 8 + n
Subtract km on both sides:
3m - km = n - 8
Factor the Left-Hand Side:
m(3 - k) = n - 8
Divide both sides by (3 - k):
m = (n - 8) / (3 - k)
Y = 1/2x+5 I think that’s it
The number of cubes with edge length ⅕ inch that will fit in the prism is: 1,920 cubes
<h3>Volume of a Rectangular Prism</h3>
Volume of a rectangular prism = length × width × height
<h3>Volume of a Cube</h3>
A cube has equal edge length. Therefore, the volume of a cube = a³, where a is the edge length.
Given the following,
Dimensions of Priya's Rectangular Prism:
2⅖ = 2.4 inches
3⅕ = 3.2 inches
2 inches
Volume of the Rectangular Prism = 2.4 × 3.2 × 2 = 15.36 in.³
Dimension of the cubes:
edge length = ⅕ inch
Volume of the cube = (⅕)³ = 0.008 in.³
The number of ⅕ inch edge cube that will fit in the prism = Volume of Prism / Volume of Cube
= 15.36/0.008 = <em>1,920 cubes </em>
Learn more about Volume of Prism on:
brainly.com/question/9761614
Answer:
a. Class width=4
b.
Class midpoints
46.5
50.5
54.5
58.5
62.5
66.5
70.5
c.
Class boundaries
44.5-48.5
48.5-52.5
52.5-56.5
57.5-60.5
60.5-64.5
64.5-68.5
68.5-72.5
Step-by-step explanation:
There are total 7 classes in the given frequency distribution. By arranging the frequency distribution into the refine form we get,
Class
Interval frequency
45-48 1
49-52 3
53-56 5
57-60 11
61-64 7
65-68 7
69-72 1
a)
Class width is calculated by taking difference of consecutive two upper class limits or two lower class limits.
Class width=49-45=4
b)
The midpoints of each class is calculated by taking average of upper class limit and lower class limit for each class.
Class
Interval Midpoints
45-48 
49-52 
53-56 
57-60 
61-64 
65-68 
69-72 
c)
Class boundaries are calculated by subtracting 0.5 from the lower class limit and adding 0.5 to the upper class interval.
Class
Interval Class boundary
45-48 44.5-48.5
49-52 48.5-52.5
53-56 52.5-56.5
57-60 56.5-60.5
61-64 60.5-64.5
65-68 64.5-68.5
69-72 68.5-72.5
