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3 years ago

PLZ HELP!! 39+(-20.4) When you answer can you plz show how you got the answer plz!!

2 answers:

7 0

It will be +18.6
Because (-20.4) is a negative number
Imagine a number line you would need 20.4 to get back to 0 since you will start at negative 20.4
39-20.4 is 18.6
So you have 18.6 left which will be on the positive side so that’s the answer

ZanzabumX [31]3 years ago

5 0

Answer:

i think is 18.6 I not sure

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Please help I've been trying to figure it out but I can't

Savatey [412]

answer : 2 1/2

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6 0

2 years ago

Will give many points! PLEASE HELP!

nataly862011 [7]

Answer:

24/5 (4.8)

Step-by-step explanation:

5:8 = 3:x

Divide both sides by 3

5:24 = 1:x

That means 24/5 = x

3 0

3 years ago

Read 2 more answers

Do you know what is 1/5 of 35

deff fn [24]

Answer:

Step-by-step explanation:

Because 35/5=7 so 1/5 of 35 would = 7

7 0

3 years ago

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Given that u = 2.89 and v = 5.7, find the value of G when:<br> a G = 5u + 2y

EleoNora [17]

Answer:

28.85

Step-by-step explanation:

Plug the values in and solve.

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G = 14.45 + 11.4

G = 25.85

5 0

3 years ago

Consider a system with one component that is subject to failure, and suppose that we have 115 copies of the component. Suppose f

castortr0y [4]

Answer:

Step-by-step explanation:

From the given information:

the mean $(\mu) = 115 \times 20$

= 2300

Standard deviation = $20 \times \sqrt{115}$

Standard deviation (SD) = 214.4761

TO find:

a) $P(x > 3500)= P(Z > \dfrac{3500-\mu}{214.4761})$

$P(x > 3500)= P(Z > \dfrac{3500-2300}{214.4761})$

$P(x > 3500)= P(Z > \dfrac{1200}{214.4761})$

$P(x > 3500)= P(Z >5.595)$

From the Z-table, since 5.595 is > 3.999

$P(x > 3500)=1-0.9999$

P(x > 3500) = 0.0001

Here, the replacement time for the mean $(\mu) = \dfrac{0+0.5}{2}$

= 0.25

Replacement time for the Standard deviation $\sigma = \dfrac{0.5-0}{\sqrt{12}}$

$\sigma = 0.1443$

For 115 component, the mean time = (115 × 20)+(114×0.25)

= 2300 + 28.5

= 2328.5

Standard deviation = $\sqrt{(115\times 20^2) +(114\times (0.1443)^2)}$

= $\sqrt{(115\times 400) +(114\times 0.02082249}$

= $\sqrt{(46000) +2.37376386}$

= $\sqrt{(46000) +(2.37376386)}$

= $\sqrt{46002.374}$

= 214.482

Now; the required probability:

$P(x > 4125) = P(Z > \dfrac{4125- 2328.5}{214.482})$

$P(x > 4125) = P(Z > \dfrac{1796.5}{214.482})$

$P(x > 4125) = P(Z >8.376)$

$P(x > 4125) =1- P(Z$

From the Z-table, since 8.376 is > 3.999

P(x > 4125) = 1 - 0.9999

P(x > 4125) = 0.0001

7 0

2 years ago