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3 years ago

How to find the y-intercept from a table AND from a graph.

Mathematics

1 answer:

ExtremeBDS [4]3 years ago

6 0

Answer:

When Finding the Y-Intercept from a Graph and Table, you are searching for the point of intersection between the equation and the y-axis. When finding the Y-Intercept from a Graph, you should find where the line from the equation crosses the y-axis. The point where the equation crosses the y-axis is the Y-Intercept.

Step-by-step explanation:

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Find all numbers whose absolute value is -9.

Neko [114]

Answer:

None

Step-by-step explanation:

A number's absolute value will always be positive

|9| = 9

|-9| = 9

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X=2y+7 3x−2y=3 solve by substitution

vazorg [7]

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Step-by-step explanation:

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3 years ago

For waht values of x do the vectors -1,0,-1), (2,1,2), (1,1, x) form a basis for R3?

DaniilM [7]

<h2>Answer:</h2>

The values of x for which the given vectors are basis for R³ is:

$x\neq 1$

<h2>Step-by-step explanation:</h2>

We know that for a set of vectors are linearly independent if the matrix formed by these set of vectors is non-singular i.e. the determinant of the matrix formed by these vectors is non-zero.

We are given three vectors as:

(-1,0,-1), (2,1,2), (1,1, x)

The matrix formed by these vectors is:

$\left[\begin{array}{ccc}-1&2&1\\0&1&1\\-1&2&x\end{array}\right]$

Now, the determinant of this matrix is:

$\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-1(x-2)-2(1)+1\\\\\\\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-x+2-2+1\\\\\\\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-x+1$

Hence,

$-x+1\neq 0\\\\\\i.e.\\\\\\x\neq 1$

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3 years ago