Explanation:
1)
a) Wavelength of red light = 700 nm
1 nanometer = 
Wavelength of red light in meter will be:
b) Wavelength of red light = 
1 meter = 39.3701 inches
Wavelength of red light in inches will be:
2)
Value of distance given = 90.123 km
1 km = 3280.84 feet
1 foot = 0.1515152 chain
Value of distance in chains:
5 x 2 = 10
3 x 3 = 9
10/9, or 1 1/9 is your answer
hope this helps
Answer:
1.195 M.
Explanation:
- We can calculate the concentration of the stock solution using the relation:
<em>M = (10Pd)/(molar mass).</em>
Where, M is the molarity of H₂SO₄.
P is the percent of H₂SO₄ (P = 40%).
d is the density of H₂SO₄ (d = 1.17 g/mL).
molar mass of H₂SO₄ = 98 g/mol.
∴ M of stock H₂SO₄ = (10Pd)/(molar mass) = (10)(40%)(1.17 g/mL) / (98 g/mol) = 4.78 M.
- We have the role that the no. of millimoles of a solution before dilution is equal to the no. of millimoles after dilution.
<em>∴ (MV) before dilution = (MV) after dilution</em>
M before dilution = 4.78 M, V before dilution = 250 mL.
M after dilution = ??? M, V after dilution = 1.0 L = 1000 mL.
∴ M after dilution = (MV) before dilution/(V after dilution) = (4.78 M)(250 mL)/(1000 mL) = 1.195 M.
Answer:
Number of moles of KClO3 required to produce 6.9 moles of oxygen gas is 4.6 moles.
Explanation:
The decomposition of potassium trioxochlorate(v) by heat to produce potassium chloride and oxygen gas is given by the balanced chemical equation below;
2KClO3(s) ----> 2KCl(s) + 3O2(g)
From the equation of the reaction, 2 moles of KClO3 produces 3 moles of oxygen gas when it decomposes under standard conditions of temperature and pressure.
The mole ratio of KClO3 to oxygen gas
is 2:3
When 6.9 moles of oxygen gas is produced, (2/3) * 6.9 moles of KClO3 will be required = 4.6 moles of KClO3
Therefore, number of moles of KClO3 required to produce 6.9 moles of oxygen gas is 4.6 moles
