3 years ago

Gases are unique because it is the only phase that

Chemistry

1 answer:

Taya2010 [7]3 years ago

5 0

Because it can be compressed.

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Is Mg(CH3COO)2 soluble or insoluble

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Answer:

It is Soluble

Explanation:

Name- Magnesium acetate

It dissolves easily in water and alcohol.

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2 years ago

Why are factory effluents harmful to aquatic<br>organisms?

svetlana [45]

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Explanation:

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2 years ago

Which statement most accurately compares the temperature of the core of the sun to its surface?

DochEvi [55]

<span>C) the core is more than a million times hotter than the surface</span>

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3 years ago

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icang [17]

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2 years ago

For a reaction A + B → products, the following data were collected. Experiment Number Initial Concentration of A (M) Initial Con

Afina-wow [57]

Answer:

Rate constant k = 1.57*10⁻⁵ s⁻¹

Explanation:

Given reaction:

$A\rightarrow B$

Expt [A] M [B] M Rate [M/s]

1 3.40 4.16 1.82*10^-4

2 4.59 4.16 3.32*10^-4

3. 3.40 5.46 1.82*10^-4

$Rate = k[A]^{x}[B]^{y}$

where k = rate constant

x and y are the orders wrt to A and B

To find x:

Divide rate of expt 2 by expt 1

$\frac{3.32*10^{-4} }{1.82*10^{-4} } =\frac{[4.59]^{x} [4.16]^{y} }{[3.40]^{x} [4.16]^{y} }\\\\x =2$

To find y:

Divide rate of expt 3 by expt 1

$\frac{1.82*10^{-4} }{1.82*10^{-4} } =\frac{[3.40]^{x} [5.46]^{y} }{[3.40]^{x} [4.16]^{y} }\\\\y =0$

Therefore: x = 2, y = 0

$Rate = k[A]^{2}[B]^{0}$

To find k

Use rate for expt 1:

$k = \frac{Rate1}{[A]^{2} } =\frac{1.82*10^{-4}M/s }{[3.40]^{2} } =1.57*10^{-5} s-1$

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2 years ago