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sleet_krkn [62]
3 years ago
13

The identities of substances are the same before and after which type of change

Chemistry
1 answer:
Alenkinab [10]3 years ago
5 0
The answer would be , a Chemical change!
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) An organic chemistry lab book gives the following solubility data for oxalic acid 9.5g/100ml water 23.7g/100ml ethanol 16.9g/1
mart [117]

Answer:

Ethanol

Explanation:

Solvent extraction is the process in which a compound transfers from one solvent to another owing to the difference in solubility or distribution coefficient between these two solvents(Science Direct).

We have to remember that oxalic acid will be extracted better into a solvent in which it is more soluble. From the data given; oxalic acid is more soluble in ethanol than in ether.

This simply means that ethanol is a better solvent for extracting oxalic acid  from water when compared to ether.

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2 years ago
What layer is made of metals and is a solid?<br> A.Mesosphere<br> B.inner core<br> C.outer core
Nookie1986 [14]
B because inner core has metal and it’s solid
7 0
3 years ago
Read 2 more answers
Which of the following is true for the equilibrium constant of a reaction? (5 pc
Slav-nsk [51]

The equilibrium constant of the reaction is represented by the symbol K. Thus, option C is the correct and accurate statement about the equilibrium constant.

<h3>What is the equilibrium constant?</h3>

The equilibrium constant is a representation of the concentration of the products and the reactants of the reaction that is raised to the powers through their stoichiometry coefficient.

Its value varies and changes at different temperatures and is not always less than 1. The equilibrium constant is the ratio of the coefficient of the products to reactants.

Therefore, option C. equilibrium constant is represented by K is true.

Learn more about the equilibrium constant here:

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8 0
2 years ago
A teaspoon of powdered caffeine can be as deadly as a teaspoon of ricin. <br><br> True or False
Darina [25.2K]

A teaspoon of caffeine is <em>NOT</em> deadly as teaspoon of ricin                                                                                                            

4 0
3 years ago
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Assuming that all the energy given off in the reaction goes to heating up only the air in the house, determine the mass of metha
nirvana33 [79]

Answer:

0.92 kg

Explanation:

The volume occupied by the air is:

35.0m\times 35.0m \times 3.2m \times \frac{10^{3}L }{1m^{3} } =3.9 \times 10^{6} L

The moles of air are:

3.9 \times 10^{6} L \times \frac{1.00mol}{22.4L} =1.7 \times 10^{5}mol

The heat required to heat the air by 10.0 °C (or 10.0 K) is:

1.7 \times 10^{5}mol \times \frac{30J}{K.mol} \times 10.0 K = 5.1 \times 10^{7}J

Methane's heat of combustion is 55.5 MJ/kg. The mass of methane required to heat the air is:

5.1 \times 10^{7}J \times \frac{1kgCH_{4}}{55.5 \times 10^{6} J } =0.92kgCH_{4}

3 0
3 years ago
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