0.12 divided by 5.676

Write in standard form<br> y=1/3(x+6)^2-9

Anon25 [30]

Answer:

$y=\frac{1}{3}x^2+4x+3$

Step-by-step explanation:

we know that

The standard form of a quadratic equation is equal to

$ax^{2} +bx+c$

we have

$y=\frac{1}{3}(x+6)^2-9$

This is the equation of a vertical parabola written in vertex form

Expanded the quadratic equation

$y=\frac{1}{3}(x^2+12x+36)-9$

Apply distributive property right side

$y=\frac{1}{3}x^2+4x+12-9$

$y=\frac{1}{3}x^2+4x+3$ ---> quadratic equation in standard form

7 0

3 years ago

What is the solution to this? Thank you for helping me 8 divided by 1 4/5

sveta [45]

Answer:

40 /9 or also can be written as 4 4/9

Step-by-step explanation:

hope this helps

7 0

4 years ago

Find the 20th term of the sequence 2, 8, 18, 32, ...

Feliz [49]

20th term of sequence is 800

<em><u>Solution:</u></em>

Given sequence is 2, 8, 18, 32

To find: 20th term of sequence

Let us first find the pattern followed by sequence

$2 \times 1 \times 1 = 2\\\\2 \times 2 \times 2 = 8\\\\2 \times 3 \times 3 = 18\\\\2 \times 4 \times 4 = 32$

So the next term is found by multiplying 2 with the square of location of term

<em><u>For nth term, we can represent by</u></em>

$a_n = 2n^2$

Where, n = 1, 2, 3, .........

n = 20

$a_{20} = 2(20)^2 = 2 \times 400 = 800$

Thus 20th term of sequence is 800

5 0

4 years ago

Please help <br> is not a exam is a activity

Mars2501 [29]

Answer:

y= 5x

Step-by-step explanation:

since each x number is 1/5 of the y, it's 5 times x = y

8 0

3 years ago

1. Find domain of the function, = ln(2 − 6 − 55).

Bingel [31]

Domain of a function

We want to find the domain of the following function:

$=ln\mleft(^2-6-55\mright)$

This means that we want to find the x-values that it can take.

<h2>STEP 1: analyzing the simplies form of the function</h2>

Let's analyze the simpliest form of the function:

$=ln(x)$

Its graph is:

Then, for the simpliest form of the function, the x-values can only be higher than 0.

This means that its domain is

domain = x > 0

<h2>STEP 2: domain of the given function</h2>

Based on the above we can deduce that for the <em>ln(x)</em> function, what is inside the parenthesis should be higher than 0 on this kind of functions.

This is that for

$=ln\mleft(^2-6-55\mright)$

then

$^2-6-55>0$ <h2>STEP 3: finding the x values that make x²-6x-55>0 (factoring)</h2>

In order to find the values of x that make

$^2-6-55>0$

we must factor it.

We want to find a pair of numbers that when multiplied give the last term (-55) and when added together give the second term (-6).

For the last term of the polynomial: -55, we have that

(-5) · 11 = 55

5 · (-11) = 11

If we add them:

-5 + 11 = 6

5 - 11 = -6

The pair of numbers that when multiplied give the last term (-55) and when added together give the second term (-6), are: 5 and -11

We use them to factor the polynomial:

$^2-6-55=(x+5)(x-11)$

Then,

$(x+5)(x-11)>0$ <h2>STEP 4: finding the x values that make (x+5)(x-11)>0 (factoring)</h2>

In order to find them, we are going to separate the factors (x+5) and (x-11) and analyze when they are positive or negative:

Combining them:

Since we are going to multiply both factors:

$(x+5)(x-11)$

We use the diagram to analyze the sign of their product:

Then

$(x+5)(x-11)>0$

when x < -5 and when x > 11. This is the domain.

Therefore, expressed in set notation:

domain = {x|x∈(-∞, -5)∪(11, ∞)}

<h2>Answer: domain = {x | x ∈ (-∞, -5)∪(11, ∞)}</h2>

5 0

1 year ago