In the usual sense, it has no inverse function. Since it is not an injection (f(0)=f(2)=0), an inverse function would have to map 0 both to 0 and 2, and that’s impossible.
However, if you restrict the domain to [1,+oo> (to make it injective), and the codomain to [-1,+oo> (to make it surjective), then it has an inverse function, given by g(y)=1+sqrt(y+1).
Y +6 =(1/2)(x+4)
y +6 = 1/2 x +2
y=1/2 x - 4
or 1/2 x -y = 4
Answer:
The line segments are parallel.
Step-by-step explanation:
First, I never have graph paper when it is needed so I suggest Geogebra.com.
Now slope is found by rise over run so I took the points on the graph and counted where they intersected with any other points on the line. AB was 2/1 which means 2. I did the same for the other line segment and found 2/1 : 2. so both of the slopes are the same so you have parallel lines.
