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2 years ago

What is the scale of the model of Venus

Mathematics

1 answer:

Firdavs [7]2 years ago

4 0

Answer:

I'll chose A

Step-by-step explanation:

You might be interested in

11900cm = yard(s)?<br> show work.

AnnZ [28]

Answer:

≈130.14 yards

Step-by-step explanation:

$\:\:\:1\:cm\:\:\:\:\:\: =0.0109361\:yards\\11900\:cm = \:x\:yards$

Cross Multiply

$x = 11900\times 0.0109361\\\\x = 130.13959\\\\x = 130.14 \:yards$

6 0

2 years ago

-2 1/3-(-5) can someone help me

Masja [62]

Convert the mixed numbers to improper fractions then find the LCD and combine.
exact form: 8/3
decimal form: 2.6
mixed number form: 2 2/3

7 0

3 years ago

What is the difference between a 30° angle and a -30° angle?

ipn [44]

Answer:

See below

Step-by-step explanation:

A 30° angle is measured 30° counterclockwise while a -30° angle is measured 30° clockwise. Therefore, you can say -30°=360-30°=330° because 30° is a reference angle located in Quadrant IV.

7 0

2 years ago

6.Suppose the Gallup Organization wants to estimate the population proportion of those who think there should be a law that woul

drek231 [11]

Answer:

A sample of $n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2$ is needed, in which E is the desired margin of error, as a proportion. If we find a decimal value, we round up to the next whole number.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In a previous study of 1012 randomly chosen respondents, 374 said that there should be such a law.

This means that $n = 1012, \pi = \frac{374}{1012} = 0.3696$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

How large a sample size is needed to be 95% confident with a margin of error of E?

A sample size of n is needed, and n is found when M = E.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$E = 1.96\sqrt{\frac{0.3696*0.6304}{n}}$

$E\sqrt{n} = 1.96\sqrt{0.3696*0.6304}$

$\sqrt{n} = \frac{1.96\sqrt{0.3696*0.6304}}{E}$

$(\sqrt{n})^2 = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2$

$n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2$

A sample of $n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2$ is needed, in which E is the desired margin of error, as a proportion. If we find a decimal value, we round up to the next whole number.

4 0

2 years ago

What is 1500000000000 in scientific notation

omeli [17]

1500000000000 in scientific notation is
1.5 * 10^12
That is because you move the decimal point 12 places to the left for it to become 1.5.
1.5 * 10^12
move the decimal point 12 places to the right and you got the original number, 1500000000000.

Hope this helps!

5 0

2 years ago

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