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vichka [17]
3 years ago
10

Find the area of wyz A. 18 cm B 36 cm C.72 cm D 144

Mathematics
1 answer:
Oliga [24]3 years ago
6 0

Answer:

36 cm^2

Step-by-step explanation:

area of triangle = length * height * 1/2

6 * 12 * 1/2 = 72 * 1/2 = 36

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Find the measure of Angle R to the nearest tenth. a. 63.8 degrees b. 67.2 degrees c. 70.9 degrees d. 61.5 degrees
Vikki [24]
The complete question in the attached figure

we know that
 tan R°=opposite side angle R/adjacent side angle R
opposite side angle R=72 units
adjacent side angle R=25 units
so
 tan R°=72/25
R=arc tan (72/25)---------> R=70.85°-------> R=70.9°

the answer is 
R=70.9°

8 0
3 years ago
Find the area of the shaded region.
Natali [406]

Answer:

3.315

Step-by-step explanation:

\frac{1}{2}  \times 1.7 \times 3.9 = 3.315

7 0
2 years ago
Solve this division problem. Write your answer as a mixed number.
MatroZZZ [7]

Answer:

3/4 / 1/2 is 1 1/2

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
In which of the following numbers does the 5 have a value that is 1/10 the value of the 5 in 95,126? A 194,538 B 570,412 C 236,9
sp2606 [1]

Answer:

A.) 194,538

Step-by-step explanation:

the value of 5 in the number 95,126 is equal to 5,000. 1/10 of the value 5,000 is 500 (500 x 10 = 5,000). the value that the 5 is at in the number 194,538 is the hundreds place,  so the calue is equal to 500, 1/10 of 5,000.

7 0
3 years ago
Find parametric equations and symmetric equations for the line. (Use the parameter t.) The line through (3, 1, 0) and perpendicu
iren2701 [21]

Answer with Step-by-step explanation:

We are given that a point (3,1,0)

Two vectors are

A=<1,1,0>

B=<0,1,1>

A\times B=\begin{vmatrix}i&j&k\\1&1&0\\0&1&1\end{vmatrix}

A\times B=i-j+k

Let v=A\times B=i-j+k

v==

r_0==

r=r_0+vt

Substitute the values then we get

r=+t

r=

The parametric equation of the line

x=x_0+at,y=y_0+bt,z=z_0+ct

Using the formula

The parametric equation of the line which is passing through the point (3,1,0) and perpendicular to both i+j and j+k is given by

x=3+t,y=1-t,z=t

The symmetric equation of the line is given by

\frac{x-x_0}{a}=\frac{y-y_0}{b}=\frac{z-z_0}{c}

Using the formula

The symmetric equation of the line which is passing through the point (3,1,0) and perpendicular to both i+j and j+k is given by

\frac{x-3}{1}=\frac{y-1}{-1}=z

8 0
3 years ago
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