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3 years ago

7

De los 740 alumnos y alumnas que tiene el colegio, el 62% tienen los ojos marrones 31% azules y el resto verdes ¿ cuantos niños

y niñas no tienen los ojos marrones? ¿Hay el doble de alumnado con ojos marrones que azules

1 answer:

MatroZZZ [7]3 years ago

8 0

Answer:

I THIK TGE ANSWER IS 93%

Step-by-step explanation:

BECAUSE I DO IN PLUS

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A truck driver is 2 hours into 1,346-Mile drive and has driven 125 Miles s far. Which of the following is the number of miles th

Mila [183]

The answer is 1,121 miles

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3 years ago

What is 4910000 in scientific notation

n200080 [17]

4.9*10 x^{6}
i hope i helped!

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3 years ago

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Eight is added to a number and the sum is doubled, the result is -11 less than the number. Find

inna [77]

If you don’t know what a number is, you should substitute it for x and make an equation with the information you have been given. This gives:

(x + 8) x 2 = x - 11

Then, solve:

2x + 16 = x - 11

2x = x -27

x = -27

This can then be checked by using the number in the original text.

-27 + 8 = -19

-19 x 2 = -38

-38 is 11 less than -27.

Hope this helps :)

3 0

3 years ago

Inverse of f(x) = x2 − 9

luda_lava [24]

To find the inverse of a function, replace every x in the equation with a y, and replace every y in the equation with an x:

$x = y^{2} - 9$

Add 9 to both sides:

$y^{2} = x + 9$

Square root both sides to get y by itself:

$y = \sqrt{x+9}$

This equation can be simplified by taking the square root of 9 out of the root:

$\sqrt{9} = 3$
$y = 3 + \sqrt{x}$

The inverse of this function is y = 3 + √x.

7 0

3 years ago

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Which function is the same as y = 3 cosine (2 (x startfraction pi over 2 endfraction)) minus 2? y = 3 sine (2 (x startfraction p

kirza4 [7]

The function which is same as the function y = 3cos(2(x +π/2)) -2 is: Option A: y= 3sin(2(x + π/4)) - 2

<h3>How to convert sine of an angle to some angle of cosine?</h3>

We can use the fact that:

$\sin(\theta) = \cos(\pi/2 - \theta)\\\sin(\theta + \pi/2) = -\cos(\theta)\\\cos(\theta + \pi/2) = \sin(\theta)$

to convert the sine to cosine.

<h3>Which trigonometric functions are positive in which quadrant?</h3>

In first quadrant (0 < θ < π/2), all six trigonometric functions are positive.
In second quadrant(π/2 < θ < π), only sin and cosec are positive.
In the third quadrant (π < θ < 3π/2), only tangent and cotangent are positive.
In fourth (3π/2 < θ < 2π = 0), only cos and sec are positive.

(this all positive negative refers to the fact that if you use given angle as input to these functions, then what sign will these functions will evaluate based on in which quadrant does the given angle lies.)

Here, the given function is:

$y= 3\cos(2(x + \pi/2)) - 2$

The options are:

$y= 3\sin(2(x + \pi/4)) - 2$
$y= -3\sin(2(x + \pi/4)) - 2$
$y= 3\cos(2(x + \pi/4)) - 2$
$y= -3\cos(2(x + \pi/2)) - 2$

Checking all the options one by one:

Option 1: $y= 3\sin(2(x + \pi/4)) - 2$

$y= 3\sin(2(x + \pi/4)) - 2\\y= 3\sin (2x + \pi/2) -2\\y = -3\cos(2x) -2\\y = 3\cos(2x + \pi) -2\\y = 3\cos(2(x+ \pi/2)) -2$

(the last second step was the use of the fact that cos flips its sign after pi radian increment in its input)
Thus, this option is same as the given function.

Option 2: $y= -3\sin(2(x + \pi/4)) - 2$

This option if would be true, then from option 1 and this option, we'd get:
$-3\sin(2(x + \pi/4)) - 2= -3\sin(2(x + \pi/4)) - 2\\2(3\sin(2(x + \pi/4))) = 0\\\sin(2(x + \pi/4) = 0$

which isn't true for all values of x.

Thus, this option is not same as the given function.

Option 3: $y= 3\cos(2(x + \pi/4)) - 2$

The given function is $y= 3\cos(2(x + \pi/2)) - 2 = 3\cos(2x + \pi) -2 = -3\cos(2x) -2$

This option's function simplifies as:

$y= 3\cos(2(x + \pi/4)) - 2 = 3\cos(2x + \pi/2) -2 = -3\sin(2x) - 2$

Thus, this option isn't true since $\sin(2x) \neq \cos(2x)$ always (they are equal for some values of x but not for all).

Option 4: $y= -3\cos(2(x + \pi/2)) - 2$

The given function simplifies to: $y= 3\cos(2(x + \pi/2)) - 2 = 3\cos(2x + \pi) -2 = -3\cos(2x) -2$

The given option simplifies to:

$y= -3\cos(2(x + \pi/2)) - 2 = -3\cos(2x + \pi ) -2\\y = 3\cos(2x) -2$

Thus, this function is not same as the given function.

Thus, the function which is same as the function y = 3cos(2(x +π/2)) -2 is: Option A: y= 3sin(2(x + π/4)) - 2

Learn more about sine to cosine conversion here:

brainly.com/question/1421592

4 0

2 years ago

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