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Liono4ka [1.6K]
3 years ago
12

Help me please this is due today

Mathematics
2 answers:
Alja [10]3 years ago
8 0

Answer:

5 cupcakes = $7.50

12 cupcakes = $18.00

18 cupcakes = $27.00

Step-by-step explanation:

Hope this helps :)

OLga [1]3 years ago
8 0
You get the answer by just multiplying and dividing by 1.5.
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If you currently have a (7) in your hand and you were to add two more cards to that (7), but the total sum of the cards is still
Molodets [167]

Answer:

king, queen, jack, ace

Step-by-step explanation:

this depends on what game's rules and scoring you're using, but I'd say the face cards

6 0
3 years ago
Can I get some help with this question plzzz
victus00 [196]
All the possible combinations are
1-1 2-1 3-1 4-1 5-1 6-1
1-2. 2-2 3-2 4-2. 5-2. 6-2
1-3 2-3. 3-3. 4-3. 5-3. 6-3
1-4. 2-4. 3-4. 4-4. 5-4. 6-4
1-5. 2-5. 3-5. 4-5. 5-5. 6-5
1-6. 2-6. 3-6. 4-6. 5-6. 6-6

What is the total for each roll?

2. 3. 4. 5. 6. 7.
3. 4. 5. 6. 7. 8
4. 5. 6. 7. 8. 9
5. 6. 7. 8. 9. 10.
6. 7. 8. 9. 10. 11.
7. 8. 9. 10. 11. 12

What roll occurs most often?

>>>>>>7<<<<<

7 occurs in 6 out of 36 possible outcomes
7 0
3 years ago
Help me, please?<br> trust me I need it.
mr_godi [17]

Answer: ∠MON = 15°

Step-by-step explanation:

∠LON = ∠LOM + ∠MON

(9x + 44) + (6x+3) = 77

9x + 6x + 44 + 3 = 77

15x + 47 = 77

15x = 30

x = 2

∠MON = 6(2) + 3 = 15

6 0
4 years ago
A single card is drawn from a standard 52 card deck. Work out the probability of choosing "an ace". Give your answer in its simp
Furkat [3]

Answer:

1/13

Step-by-step explanation:

Total cards = 52

No: of aces in the cards= 4

Probability = 4/52 = 1/13

I hope im right!!1

5 0
3 years ago
I don’t understand how to do it ?
Temka [501]

We know that Sum of Angles in a Triangle is Equal to 180°

Here EBF is a Triangle

⇒ m∠EBF + m∠BEF + m∠EFB = 180°

⇒ 60° + 40° + m∠EFB = 180°

⇒ 100° + m∠EFB = 180°

⇒ m∠EFB = 180° - 100°

⇒ m∠EFB = 80°

As Line m and Line p are Parallel Lines :

Alternate Interior Angles are Equal, here Alternate Interior Angles are m∠BEF and m∠ABE

⇒ m∠BEF = m∠ABE

⇒ m∠ABE = 40°

We know that Vertically Opposite Angles are Equal, Here m∠GFI and m∠EFB are Vertically Opposite Angles.

⇒ m∠GFI = m∠EFB

⇒ m∠GFI = 80°

We can notice that m∠DEB and m∠BEF form a Linear Pair

⇒ m∠DEB + m∠BEF = 180°

⇒ m∠DEB + 40° = 180°

⇒ m∠DEB = 180° - 40°

⇒ m∠DEB = 140°

We can notice that Sum of Angles m∠CBF and m∠EBF and m∠ABE is 180°

⇒ m∠CBF + m∠EBF + m∠ABE = 180°

⇒ m∠CBF + 60° + 40° = 180°

⇒ m∠CBF + 100° = 180°

⇒ m∠CBF = 180° - 100°

⇒ m∠CBF = 80°

We can notice that m∠BFG and m∠EFB form a Linear Pair

⇒ m∠BFG + m∠EFB = 180°

⇒ m∠BFG + 80° = 180°

⇒ m∠BFG = 180° - 80°

⇒ m∠BFG = 100°

We know that Vertically Opposite Angles are Equal, Here m∠BFG and m∠IFE are Vertically Opposite Angles.

⇒ m∠BFG = m∠IFE

⇒ m∠IFE = 100°

3 0
3 years ago
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