All categories

3 years ago

What is the surface area of the right cone below?

Mathematics

1 answer:

docker41 [41]3 years ago

3 0

Answer:

A=πr(r+h2+r2)

Step-by-step explanation:

A. hope this helps.

You might be interested in

Two sidewalks in a park are represented by lines on a coordinate grid. Two points on each of the lines are shown in the tables.

algol [13]

Answer:

y = 2x + 1 ;

y - 3 = - 3(x - 1) ; y = - 3x + 6 ;

Independent ;

(1, 3)

Step-by-step explanation:

Given the data:

Sidewalk 1:

x __ y

2 _ 5

0 _ 1

Sidewalk 2:

x __ y

1 _ 3

3 _ -3

Equation for sidewalk 1 in slope - intercept form:

Slope intercept form:

y = mx + c

c = intercept ; m = slope

m = (change in y / change in x)

m = (1 - 5) / (0 - 2) = - 4 / - 2 = 2

Y intercept ; value of y when x = 0

(0, 1) ; y = 1

Hence, c = 1

y = 2x + 1

Sidewalk 2:

Point slope form:

y - y1 = m(x - x1)

m = slope

m = = (-3 - 3) / (3 - 1) = - 6/2 = - 3

Point (x1, y1) = (1, 3)

y - 3 = - 3(x - 1)

To slope intercept form:

y - 3 = - 3(x - 1)

y - 3 = - 3x + 3

y = - 3x + 3 + 3

y = - 3x + 6

Since the slope of both lines are different, intersection will be at single point and will have a single solution. This makes it independent.

Using substitution method :

y = 2x + 1 - - - (1)

y = - 3x + 6 - - - (2)

Substitute (1) into (2)

2x + 1 = - 3x + 6

2x + 3x = 6 - 1

5x = 5

x = 1

From (1)

y = 2(1) + 1

y = 2 + 1

y = 3

Coordinate of the point of intersection = (1, 3)

5 0

3 years ago

Solve the equation<br> -3x + 1 + 10x = x + 4<br> 0 x = 1/2<br> х<br> =<br> x = 12<br> X = 18

pav-90 [236]

Answer:

Step-by-step explanation:

-3x + 1 + 10x = x + 4

-1 -1

7x = x + 3

-x -x

6x = 3

÷6 ÷6

x = 1/2

8 0

3 years ago

Find the slope and the y-intercept of the graph of y=11+1.5x.

Anni [7]

Honestly man i don’t know Im in 6th grade bro

6 0

3 years ago

Read 2 more answers

HELP!!!!

ch4aika [34]

Answer:

$8 y^{50}$

Step-by-step explanation:

Given (64 y Superscript 100 Baseline) Superscript one-half.

Let us write it into an equation.

$\left(64 y^{100}\right)^{\frac{1}{2}}$

Apply radical rule: $\sqrt[n]{a}=a^{\frac{1}{2}}$ and $a^{m+n}=a^m+a^n$

$\begin{aligned}\left(64 y^{100}\right)^{\frac{1}{2}} &=\sqrt[2]{64 y^{100}} \\&=\sqrt[2]{8^{2} y^{50} y^{50}} \\&=\sqrt[2]{8^{2}\left(y^{50}\right)^{2}} \\&=8 y^{50}\end{aligned}$

Hence, $8 y^{50}$ is equivalent to (64 y Superscript 100 Baseline) Superscript one-half.

8 0

3 years ago

Select all the equations that are true. 24 x − 8 = 8 ( 3 x − 1 ) 24 x − 8 = 8 ( 3 x − 1 ) 6 m − 15 = 3 ( 2 m − 5 ) 6 m − 15 = 3

galina1969 [7]

Answer:

$24x - 8 = 8 ( 3 x - 1 )$

$6 m - 15 = 3 ( 2 m - 5 )$

$-7 x - 1 = - 1 ( 7 x + 1 )$

$-8 x -12 y - 16 = - 4 ( 2 x + 3 y + 4 )$

Step-by-step explanation:

Required

Select which of the equation is true

$24x - 8 = 8 ( 3 x - 1 )$

Open the bracket on the right hand side

$24x - 8 = 8 * 3 x - 8 *1$

$24x - 8 = 24x - 8$

Both sides of the equation are equal.

Hence, this equation is true

$6 m - 15 = 3 ( 2 m - 5 )$

Open the bracket on the right hand side

$6m - 15 = 3 * 2m - 3 * 5$

$6m - 15 = 6m - 15$

Both sides of the equation are equal.

Hence, this equation is true

$-7 x - 1 = - 1 ( 7 x + 1 )$

Open the bracket on the right hand side

$-7x - 1 = -1 * 7x -1 * 1$

$-7x - 1 = -7x -1$

Both sides of the equation are equal.

Hence, this equation is true

$16 a + 24 b = 8 ( 8 a + 16 b )$

Open the bracket on the right hand side

$16a + 24b = 8 * 8a + 8 * 16b$

$16a + 24b = 64a + 128b$

Both sides of the equation are not equal.

Hence, this equation is false

$-8 x -12 y - 16 = - 4 ( 2 x + 3 y + 4 )$

Open the bracket on the right hand side

$-8 x -12 y - 16 = - 4* 2 x -4 * 3 y -4 * 4$

$-8 x -12 y - 16 = -8x -12y -16$

Both sides of the equation are equal.

Hence, this equation is true

8 0

3 years ago