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3 years ago

What is the product of 2p + q and –3q – 6p + 1?

Mathematics

2 answers:

pashok25 [27]3 years ago

4 0

Answer:

B -> –12p2– 12pq + 2p – 3q2 + q

Step-by-step explanation:

Umnica [9.8K]3 years ago

3 0

-12p^2 - 12pq + 2p -3q^2 + q

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3 years ago

A TV was bought for $18,950 and old at a loss of $4780.Find the selling price

Juliette [100K]

Answer:

$23729.19 ( approx )

Step-by-step explanation:

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3 years ago

Help me guys <br> thx so much

navik [9.2K]

Answer:

Option D, $10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}$

Step-by-step explanation:

<u>Step 1: Multiply</u>

<u /> $(\sqrt{10x^4} -x\sqrt{5x^2} )*(2\sqrt{15x^4} + \sqrt{3x^3})\\ (\sqrt{10 * x^2 * x^2} -x\sqrt{5 * x^2} ) * (2\sqrt{15 * x^2 * x^2} +\sqrt{3 * x^2 * x})\\(x^2\sqrt{10} -x^2\sqrt{5} )*(2x^2\sqrt{15} +x\sqrt{3x}) \\\\$

$(x^2\sqrt{10}*2x^2\sqrt{15} )+(x^2\sqrt{10}*x\sqrt{3x} ) + (-x^2\sqrt{5} *2x^2\sqrt{15}) + (-x^2\sqrt{5} *x\sqrt{3x}$

$(2x^4\sqrt{150} ) + (x^3\sqrt{30x}) + (-2x^4\sqrt{75}) + (-x^3\sqrt{15x} )$

$2x^4\sqrt{5^2*6} + x^3\sqrt{30x} -2x^4\sqrt{5^2*3} -x^3\sqrt{15x}$

$10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}$

Answer: Option D, $10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}$

6 0

3 years ago

Read 2 more answers

The question is

PilotLPTM [1.2K]

The unknown side lengths are

Large triangle 10

Medium triangle 2

Small triangle 12/5 or 2.4

Step-by-step explanation:

EFD to ABC is 0.4 or 2/5

EFD to GHI is 0.24 or 6/25

ABC to GHI is 0.6 or 6/10

5 0

3 years ago