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Lady bird [3.3K]
3 years ago
9

What is the product of 2p + q and –3q – 6p + 1?

Mathematics
2 answers:
pashok25 [27]3 years ago
4 0

Answer:

B  ->   –12p2– 12pq + 2p – 3q2 + q

Step-by-step explanation:

Umnica [9.8K]3 years ago
3 0
-12p^2 - 12pq + 2p -3q^2 + q
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Ava is in charge of bringing bottled water to a party that has 42 guests.
olya-2409 [2.1K]

Answer:

a - about 3 packs cause you have to round up

b - $50.76

Step-by-step explanation:

First you divide 42 and 18.

42/18=2.33

You have to round up cause you can't have half of a pack, you can't just buy half of a pack.

So, it is rounded to 3 packs.

Next you have to multiply the number of packs and the cost of each pack of water bottles.

16.92*3=$50.76

a - you have to buy 3 packs

b - the total cost is $50.76

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3 years ago
Help me multiple choice math question
nikitadnepr [17]

Answer:

the answer is C

Step-by-step explanation:

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3 years ago
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A pipe is leaking at the rate of 32 fluid ounces per minute. Use dimensional analysis to find out how many gallons the pipe is l
lianna [129]

well first think about it, 60 min in an hour, so 32 fluid ounces times 60 = 1920 fluid ounces, from there you can convert fluid ounces to practically anything, for instance, 1920 fluid ounces = 24 cups.

go to this address to find out more.

https://www.google.com/search?q=another+name+for+observations&rls=com.microsoft:en-US:IE-Address&ie=...

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A teacher can grade 25 papers in 4 hours. How many papers can he grade in 6 hours?
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6hours(25papers/hour)=150 papers

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3 years ago
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Given the position of the particle, what the position(s) of the particle when it’s at rest
choli [55]

The position function of a particle is given by:

X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t

The velocity function is the derivative of the position:

\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}

The particle will be at rest when the velocity is 0, thus we solve the equation:

2t^2-9t-18=0

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

Substituting:

\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}

We have two possible answers:

\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

undefined

6 0
1 year ago
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