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3 years ago

Write the given numbers in standard notation, maintaining the same number of significant figures.

Chemistry

1 answer:

svetlana [45]3 years ago

4 0

Answer:

0.0761.

0.0059.

Explanation:

Hello!

In this case, since the writing of numbers in standard notation given the scientific notation requires adding zeros to the left of the first nonzero digit, for the first number, we need to add two zeros as seven is the third digit position:

0.0761.

Next, we need to add three zeros as 5 would be the fourth digit:

0.0059.

Best regards!

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Calculate the number of moles of Cu in 3.8×10213.8×1021 atoms of Cu.

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Answer:

6.3×10⁻³ moles of Cu

Explanation:

The relation is, that 1 mol of particles are contained by 6.02×10²³ particles.

This is Avogadro's number that explains that: one mole determines the number of fundamental units that are contained in a constant number but they do not depend on the type of material or the type of particle, and this quantity is 6.02 × 10²³

We can make a rule of three:

6.02×10²³ atoms are contained 1 in mol of Cu

Therefore, 3.8×10²¹ atoms will be contained in (3.8×10²¹ . 1) / NA = 6.3×10⁻³ moles

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4 years ago

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3 years ago

Which of the following solutions has the HIGHEST hydroxide-ion concentration?a) 0.1 M HClb) 0.1 M H2SOc) a buffer solution with

Alexus [3.1K]

Answer:

c) a buffer solution with pH= 5

Explanation:

The equation of hydrolisis of water is:

1x10⁻¹⁴ = [H⁺] [OH⁻]

That means if we know [H⁺] we can find hydroxide-ion concentration and vice versa.

a) HCl 0.1M = [H⁺] = 0.1M;

1x10⁻¹⁴ / [H⁺]

1x10⁻¹⁴/ 0.1M = [OH⁻]

1x10⁻¹³M = [OH⁻] hydroxide- ion concentration.

b) 0.1M H₂SO₄ = 0.2M [H⁺]

1x10⁻¹⁴/ 0.2M = [OH⁻]

5x10⁻¹⁴M = [OH⁻]

c) pH = 5.

[H⁺] = 1x10⁻⁵M

1x10⁻¹⁴/ 1x10⁻⁵M = [OH⁻]

1x10⁻⁹M = [OH⁻]

d) pOH = 12.

[OH⁻] = 1x10⁻¹²M

That means risht answer is:

<h3>c) a buffer solution with pH= 5</h3>

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4 years ago

The molecules in a sample of oxygen gas are in constant motion. What does an increase in temperature indicate about the movement

Basile [38]

Answer:

An increase in temperature indicates that the molecules of gas speed up.

Explanation:

The molecular kinetic theory states that the average kinetic energy of gas particles (molecules) is proportional to the absolute (Kelvin) temperature of the gas, and all gases at the same temperature have the same average kinetic energy.

Therefore, as the temperature increases so the kinetic energy increases.

It is also known that the kinetic energy is proportional to the squared speed of the particles, therefore the higher the kinetic energy the average speed of the molecules:

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4 0

3 years ago

Read 2 more answers

What is the maximum mass of ammonia that can be formed when 36.52 grams of nitrogen gas reacts with 10.62 grams of hydrogen gas

k0ka [10]

The maximum mass of NH₃ that can be formed when 36.52 g of N₂ reacts with 10.62 g of H₂ is 44.35 g

<h3>Balanced equation </h3>

N₂ + 3H₂ —> 2NH₃

Molar mass of N₂ = 14 × 2 = 28 g/mol

Mass of N₂ from the balanced equation = 1 × 28 = 28 g

Molar mass of H₂ = 2 × 1 = 2 g/mol

Mass of H₂ from the balanced equation = 3 × 2 = 6 g

Molar mass of NH₃ = 14 + (3×1) = 17 g/mol

Mass of NH₃ from the balanced equation = 2 × 17 = 34 g

SUMMARY

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂ to produce 34 g of NH₃

<h3>How to determine the limiting reactant </h3>

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

36.52 g of N₂ will react with = (36.52 × 6) / 28 = 7.83 g of H₂

From the above calculation, we can see that only 7.83 g out of 10.62 g of H₂ are required to react completely with 36.52 g of N₂.

Therefore, N₂ is the limiting reactant

<h3>How to determine the maximum mass of NH₃ produced </h3>

From the balanced equation above,

28 g of N₂ reacted to produce 34 g of NH₃

Therefore,

36.52 g of N₂ will react to produce = (36.52 × 34) / 28 = 44.35 g of NH₃

Thus, the maximum mass of NH₃ obtained from the reaction is 44.35 g

Learn more about stoichiometry:

brainly.com/question/14735801

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2 years ago